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Fiesta28 [93]
3 years ago
7

For the month of march, Kasey plans to vacuum her floor every fourth day and clean her bathroom every seventh day if she begins

this march 1, on what day of the month will she do both jobs?
Mathematics
1 answer:
Alexeev081 [22]3 years ago
4 0

Answer: March 28

Step-by-step explanation:

Solve for this by checking for the lowest common multiple of 7 and 4.

Multiples of 7: 7, 14, 21, 28, 35

Multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32

Lowest is 28 so on March 28th she both will vacuum her floor and clean her bathroom.

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The radius of a right circular cylinder is increasing at a rate of 9 inches per minute and the height is decreasing at a rate of
pav-90 [236]

Answer:

\frac{dA}{dt}=1840.97 in^{2}/min      

Step-by-step explanation:

The equation of the surface of the right circular cylinder is:

A=2\pi rh+2\pi r^{2}=2\pi(rh+r^{2})

Now, the rate change of this area will be:

Using the change rule

\frac{dA}{dt}=\frac{\partial A}{\partial r}\frac{\partial r}{\partial t}+\frac{\partial A}{\partial h}\frac{\partial h}{\partial t}

Where:                          

  • \frac{\partial h}{\partial t} is the rate change of height (-16 in/min)
  • \frac{\partial r}{\partial t} is the rate change of radius (9 in/min)

 

\frac{dA}{dt}=\frac{\partial A}{\partial r}9+\frac{\partial A}{\partial h}(-16)

\frac{dA}{dt}=2\pi(h+2r)9-2\pi r16=2\pi((h+2r)9-16r)

Now, r = 16 and h = 29

\frac{dA}{dt}=2\pi((29+2*16)9-16*16)

\frac{dA}{dt}=1840.97 in^{2}/min      

I hope it helps you!

8 0
4 years ago
The tables show some input and output values:
Radda [10]
A because one input can have only one output
3 0
4 years ago
Read 2 more answers
A school bus is moving 26.8 m/s on flat ground when it begins to accelerate at 4.73 m/s^2. How much time does it take to travel
leva [86]

The school bus will take 5.34 seconds to travel 95.1 m if the bus is moving 26.8 m/s on flat ground when it begins to accelerate at 4.73 m/s².

<h3>What is a quadratic equation?</h3>

Any equation of the form \rm ax^2+bx+c=0 where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}

We have:

A school bus is moving 26.8 m/s on flat ground when it begins to accelerate at 4.73 m/s².

From the second equation of motion:

\rm s = u + \dfrac{1}{2}at^2

We have given:

s = 95.1 m

u = 26.8 m/s

a = 4.73 m/s²

\rm 95.1 = 26.8 + \dfrac{1}{2}(4.73)t^2

The above equation is a quadratic equation:

After simplification:

\rm \dfrac{4.73}{2}t^2=68.3

\rm t^2=28.879

t = 5.373 seconds ≈ 5.34 seconds

Thus, the school bus will take 5.34 seconds to travel 95.1 m if the bus is moving 26.8 m/s on flat ground when it begins to accelerate at 4.73 m/s².

Learn more about quadratic equations here:

brainly.com/question/2263981

#SPJ1

4 0
2 years ago
Write the equation of a line that passes through the given point and is perpendicular to the given line (6,12) and y=5x+3
RoseWind [281]

Answer:

y = -1/5x + 13.2

Step-by-step explanation:

y = -1/5x + b

12 = -1/5(6) + b

12 = -6/5 + b

13.2 = b

y = -1/5x + 13.2

7 0
3 years ago
7:x=2:3<br> Solve the equation
g100num [7]

Answer:

10.5 =x

Step-by-step explanation:

We can rewrite this as a ratio

7          2

---- = ------

x         3

Using cross products

7*3 = 2x

Divide each side by 2

21 /2 = 2x/2

10.5 =x

8 0
3 years ago
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