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telo118 [61]
3 years ago
9

I need help with this math question real quick

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
8 0
<h2><u>Answer:</u></h2>

1- Length of PQ: 233

2-Area of rectangle: 21840

3- Length of RS: 241.87

4-Area of triangle: 12600

<h2><u>Explanation-</u></h2>

to find the lengths of RS and PQ use the pythagorean theorem a^{2} +b^{2}= c^{2}

to find area of triangle use A=  \frac{BxH}{2} (area = base times height divided by 2)

to find area of rectangle useA= LxW (area= length times width

noname [10]3 years ago
8 0

Answer:

i really need to ask my q thnak you

Step-by-step explanation:

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5 less than half a number, x<br><br> please help i will give you the brainliest answer
Karo-lina-s [1.5K]

Answer: 1/2x -5

Step-by-step explanation:

Half of x , less 5. (5 less just means subtract)

5 0
3 years ago
5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.
s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of <em>(</em><em>124</em><em> </em><em>and</em><em> </em><em>244</em><em>)</em><em> </em>and <em>(</em><em>4424</em><em> </em><em>and</em><em> </em><em>2111</em><em>)</em><em> </em>are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

<em>#initialize</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>named</em><em> </em><em>gcd</em><em> </em><em>which</em><em> </em><em>takes</em><em> </em><em>in</em><em> </em><em>two</em><em> </em><em>parameters</em><em> </em>

if a>b:

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>greater</em><em> </em><em>than</em><em> </em><em>b</em>

return gcd (b, a)

<em>#if</em><em> </em><em>true</em><em> </em><em>interchange</em><em> </em><em>the</em><em> </em><em>Parameters</em><em> </em><em>and</em><em> </em><em>Recall</em><em> </em><em>the</em><em> </em><em>function</em><em> </em>

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

<em>#even</em><em> </em><em>numbers</em><em> </em><em>leave</em><em> </em><em>no</em><em> </em><em>remainder</em><em> </em><em>when</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>2</em><em>,</em><em> </em><em>checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>are</em><em> </em><em>even</em><em> </em>

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>odd</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>even</em><em> </em>

return gcd(a, b/2)

else :

return gcd(a, b-a)

<em>#since</em><em> </em><em>it's</em><em> </em><em>a</em><em> </em><em>recursive</em><em> </em><em>function</em><em>,</em><em> </em><em>it</em><em> </em><em>recalls</em><em> </em><em>the function</em><em> </em><em>with </em><em>new</em><em> </em><em>parameters</em><em> </em><em>until</em><em> </em><em>a</em><em> </em><em>certain</em><em> </em><em>condition</em><em> </em><em>is</em><em> </em><em>satisfied</em><em> </em>

print(gcd(124, 244))

print()

<em>#leaves</em><em> </em><em>a</em><em> </em><em>space</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>output</em><em> </em>

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

6 0
3 years ago
The distance between R and T on the coordinate grid is ___ units. (Input whole numbers only.)
gogolik [260]
15 units of distance. So 15
7 0
3 years ago
Select all of the points that are solutions to the system of linear inequalities that is listed below 10x + 4y &lt; 12 8x -3y &g
liberstina [14]

Answer:

(3, -8) and (2, -10)

Step-by-step explanation:

Given

10x + 4y < 12

8x - 3y > 20

Required

Select the true coordinate points in (3, -8) (2, 5) (-5, 1) (10, 3) (2, -10)

(3, -8)

x = 3 and y = -8

10x + 4y < 12

10 * 3 + 4 * -8 < 12

30 - 32 < 12

-2 < 12 --- True

8x - 3y > 20

8 * 3 - 3 * -8> 20

24 +24> 20

48> 20 --- True

(2, 5)

x = 2 and y = 5

10x + 4y < 12

10 * 2 + 4 * 5 < 12

20 + 20 < 12

40 < 12 --- False (No need to check the other inequality)

(-5, 1)

x = -5 and y = 1

10x + 4y < 12

10 * -5 + 4 * 1 < 12

-46 < 12 --- True

8x - 3y > 20

8 * -5 - 3 * 1 > 20

-43 > 20 --- False

(10, 3)

x = 10 and y = 3

10x + 4y < 12

10 * 10 + 4 * 3 < 12

112 < 12 --- False (No need to check the other inequality)

(2, -10)

x = 2 and y = -10

10x + 4y < 12

10 * 2 + 4 * -10 < 12

-20 < 12 --- True

8x - 3y > 20

8 * 2 - 3 * -10 > 20

46 > 20 --- True

Hence, the solution to the inequalities are:

(3, -8) and (2, -10)

4 0
3 years ago
All 231 students in math club went on a field trip some rode in vans that held 7 people and some rode on buses that held 25 peop
MariettaO [177]

Answer:

8 vans

7 buses

Step-by-step explanation:

Let there be "b" buses

and "v" vans

Since 7 people is the capacity of vans, the total capacity is

7v

Also, since 25 people is the capacity of 1 bus, the total capacity is

25b

In total 231 people, so we can write our first equation as:

7v + 25b = 231

Now, we know there are 15 vehicles (bus + vans) in total, so we can write our 2nd equation as:

v + b = 15

Now, we solve for v and b. Let's solve the 2nd equation for v and substitute that into 1st and solve for b first:

v + b = 15

v = 15 - b

Now,

7v + 25b = 231\\7(15-b) + 25b = 231\\105-7b+25b=231\\18b=126\\b=7

Hence, there are 7 buses

Since 15 vehicles in total, the number of vans is:

15 - 7 = 8 vans

So,

8 vans

7 buses

8 0
4 years ago
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