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telo118 [61]
2 years ago
9

I need help with this math question real quick

Mathematics
2 answers:
soldi70 [24.7K]2 years ago
8 0
<h2><u>Answer:</u></h2>

1- Length of PQ: 233

2-Area of rectangle: 21840

3- Length of RS: 241.87

4-Area of triangle: 12600

<h2><u>Explanation-</u></h2>

to find the lengths of RS and PQ use the pythagorean theorem a^{2} +b^{2}= c^{2}

to find area of triangle use A=  \frac{BxH}{2} (area = base times height divided by 2)

to find area of rectangle useA= LxW (area= length times width

noname [10]2 years ago
8 0

Answer:

i really need to ask my q thnak you

Step-by-step explanation:

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Which of the following equals cos 80° ?<br> A. sin 100°<br> B. sin 20°<br> C. sin 10°<br> D. sin 80°
zysi [14]

Answer:

C

Step-by-step explanation:

8 0
3 years ago
Two of the statements are true; one is a lie.
Temka [501]

Answer:

Statement 3

Step-by-step explanation:

∠GAF ≅ ∠TAE

Since, there is no relation between these angles,

Therefore, statement is False.

∠TAE and ∠FAH are complementary.

If the sum of the two angles is 90°, pair of angles is said to be complimentary angles.

Therefore, this statement is False.

∠TAF is obtuse.

Measure of obtuse angle is more than 90°

From the given picture, measure of ∠TAF = m∠TAH + m∠HAF

                                                                      = 90° + 50°

                                                                      = 140°

Here, m∠TAF > 90°

Therefore, ∠TAF is an obtuse angle.

Statement (3) is the correct statement.

8 0
3 years ago
Pleaseeehelp me !!!!
Volgvan

Answer:

Go on to photo math it's good for equations

8 0
3 years ago
An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.
Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

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The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0.\overline 1 yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0.\overline 1 yd. =  (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

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The mass of the steel  pad, m₁ = ρ × V₁

∴ The mass of the steel  pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

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