The value of the car is January 2003 is $199,148.54.
<h3>What is the value of the car?</h3>
Depreciation is the rate of decline in the value of an asset with the passage of time.
The exponential equation that can be used to determine the value of the car is:
Value of the car = purchase value(1 - rate of decline)^time
400,000 x (1 - 0.16)^(2003 - 1999)
400,000 x (0.84^4) = $199,148.54
To learn more about depreciation, please check: brainly.com/question/15085226
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Answer:
a) x = 30°
b) mRS = x = 30°
mST = 4x = 4(30°) = 120°
mTU = 4x = 4(30°) = 120°
mUR = 3x = 3(30°) = 90°
Question:
The complete question as found on Chegg website:
In the diagram below, secants PT and PU have been drawn from exterior point P such that the four arcs
intercepted have the following ratio of measurements:
mRS : mST :MTU : mUR=1:4:4:3
(a) If mRS = x, then write an equation that could be used to solve for x
and find the value of x.
(b) State the measure of each of the four arcs.
mRS =
mST =
MTU
MUR =
Step-by-step explanation:
Find attached the diagram related to the question
mRS : mST : mTU : mUR = 1:4:4:3
Since mRS = x
Writing the ratios of the measure of angle in terms of mRS:
mST = 4× mRS = 4×x = 4x
mTU = 4× mRS = 4×x = 4x
mUR= 3× mRS = 3×x = 3x
The sum of measure the 4 measures of arc = 360° (sum of angle in a circle)
mRS + mST + mTU + mUR = 360°
x + 4x + 4x + 3x = 360
12x = 360
x = 360/12
x = 30°
b) The measure of angle
mRS = x = 30°
mST = 4x = 4(30°) = 120°
mTU = 4x = 4(30°) = 120°
mUR = 3x = 3(30°) = 90°
(5 3/10) (m) + (5 3/10) (m) + (5 3/10) (m) + (5 3/10) (m)
P = 53/10 + 5 3/10 + 5 3/10 + 5 3/10
P = 53/10 + 53/10 + 5 3/10 + 5 3/10
P = 53/5 + 5 3/10 + 5 3/10
P = 53/5 + 53/10 + 5 3/10
P = 159/10 + 5 3/10
P = 159/10 + 53/10
P = 106/5
P = 21 1/5 meters
Answer: 21 1/5 meters (Decimal: 21.2m)
Hope that helps!!!! Have a great day!!!! : )
Answer:
4
Step-by-step explanation:
2+2 =4
Answer:
12? I'm not sure. That's the answer I think?