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3 years ago

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Use the digits 0 - 9 to fill in the blank.

d="TexFormula1" title="243 \frac{1}{5} = blank" alt="243 \frac{1}{5} = blank" align="absmiddle" class="latex-formula">

1 answer:

Tresset [83]3 years ago

8 0

Answer:

use 0-9 to fill in blanks

Step-by-step explanation:

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Name two solutions for each inequality.

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So,

#1: $n \geq 3 \frac{11}{16} + 4 \frac{1}{2}$

Convert to like improper fractions.
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Add.
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So, one solution could be $8 \frac{3}{16}$ .

Another solution could by 9. There is also 10, 11, 12, etc., and all numbers in between.

#2: $k \ \textless \ 6 \frac{2}{5} * 15$

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Multiply.
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Cross-cancel, and we have our final result.
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fter production, a computer component is given a quality score of A, B, and C. On the average U of the components were given a q

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Answer:

Follows are the solution to this question:

Step-by-step explanation:

In the given question some of the data is missing so, its correct question is defined in the attached file please find it.

Let

A is quality score of A

B is quality score of B

C is quality score of C

$\to P[A] =0.55\\\\\to P[B] =0.28\\\\\to P[C] =0.17\\$

Let F is a value of the content so, the value is:

$\to P[\frac{F}{A}] =0.15\\\\\to P[\frac{F}{B}] =0.12\\\\\to P[\frac{F}{C}] =0.14\\$

Now, we calculate the tooling value:

$\to p[\frac{C}{F}]$

using the baues therom:

$\to p[\frac{C}{F}] = \frac{p[C] \times p[\frac{F}{C} ]}{p[A] \times p[\frac{F}{A}] + p[B] \times p[\frac{F}{B}]+p[C] \times p[\frac{F}{C}] }$

$= \frac{ 0.17 \times 0.14 }{0.55 \times 0.15 + 0.28 \times 0.12 + 0.17 \times 0.14 } \\\\= \frac{0.0238}{0.0825 + 0.0336 + 0.0238} \\\\= \frac{0.0238}{0.1399} \\\\=0.1701$

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