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Ksju [112]
2 years ago
6

Which expression is equivalent to the expression below? StartFraction 6 c squared 3 c Over negative 4 c 2 EndFraction divided by

StartFraction 2 c 1 Over 4 c minus 2 EndFraction.
Mathematics
1 answer:
Fudgin [204]2 years ago
7 0

The given equation (6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2) is equivalent to the expression -3c.

Given that, the expression can be written as.

(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)

By simplifying the above equation,

\dfrac{6c^2+3c}{-4c+2}\div \dfrac{2c+1}{4c-2}

By taking out the common terms from the equation,

\dfrac{3c(2c+1)}{2(-2c+1)}\div\dfrac{2c+1}{2(2c-1)}

By simplifying the above equation by cancel out the common factors.

\dfrac{3c}{-2c+1} \div \dfrac{1}{2c-1}

Now, by taking (-1) common from (-2c+1) we get,

\dfrac{3c}{-1(2c-1)} \div \dfrac{1}{2c-1}

By simplifying the above equation, we get the expression,

-3c

So the given equation (6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2) is equivalent to the expression -3c.

For more details, follow the link given below.

brainly.com/question/1301963.

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Easy, need help, thanks.
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