The given equation
is equivalent to the expression -3c.
Given that, the expression can be written as.
![(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)](https://tex.z-dn.net/?f=%286c%5E2%2B3c%29%2F%28-4c%2B2%29%5Cdiv%20%282c%2B1%29%2F%284c-2%29)
By simplifying the above equation,
![\dfrac{6c^2+3c}{-4c+2}\div \dfrac{2c+1}{4c-2}](https://tex.z-dn.net/?f=%5Cdfrac%7B6c%5E2%2B3c%7D%7B-4c%2B2%7D%5Cdiv%20%5Cdfrac%7B2c%2B1%7D%7B4c-2%7D)
By taking out the common terms from the equation,
![\dfrac{3c(2c+1)}{2(-2c+1)}\div\dfrac{2c+1}{2(2c-1)}](https://tex.z-dn.net/?f=%5Cdfrac%7B3c%282c%2B1%29%7D%7B2%28-2c%2B1%29%7D%5Cdiv%5Cdfrac%7B2c%2B1%7D%7B2%282c-1%29%7D)
By simplifying the above equation by cancel out the common factors.
![\dfrac{3c}{-2c+1} \div \dfrac{1}{2c-1}](https://tex.z-dn.net/?f=%5Cdfrac%7B3c%7D%7B-2c%2B1%7D%20%5Cdiv%20%5Cdfrac%7B1%7D%7B2c-1%7D)
Now, by taking (-1) common from (-2c+1) we get,
![\dfrac{3c}{-1(2c-1)} \div \dfrac{1}{2c-1}](https://tex.z-dn.net/?f=%5Cdfrac%7B3c%7D%7B-1%282c-1%29%7D%20%5Cdiv%20%5Cdfrac%7B1%7D%7B2c-1%7D)
By simplifying the above equation, we get the expression,
![-3c](https://tex.z-dn.net/?f=-3c)
So the given equation
is equivalent to the expression -3c.
For more details, follow the link given below.
brainly.com/question/1301963.