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3 years ago

I did the math and ended up with 3,033 but that is waaaay over his savings please help

Mathematics

2 answers:

rewona [7]3 years ago

8 0

Answer: Dave Will have $881 left to put into his savings.

Step-by-step explanation

So Lets look at this, He has $2000 to spend, he buys 3 tables for $58 each, 12 chairs for $65 each, and a watch for $165.

(2000-(3*58)-(12*65)-165)=881

stealth61 [152]3 years ago

3 0

Answer: is $881.00

Multiply 3x58, 12x65 and 1x165 gives you a total of 1,119 subtract this with your actual money which is 2,000 gives your a total of 881.00 towards your savings account

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Can two positive integers have their H.C.F and L.C.M as 12 and 512 respectively? justify.

DaniilM [7]

Here is your answer

Reason:

H.C.F. divides the L.C.M. completely.

Here 512 is not completely divided by 12

So, two numbers can't have their H.C.F and L.C.M as 12 and 512 respectively.

HOPE IT IS USEFUL

7 0

3 years ago

Read 2 more answers

10.

SpyIntel [72]

Answer:

Step-by-step explanation:

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6 0

3 years ago

Can someone explain how to do this, please?

BartSMP [9]

Answer:

$\sqrt{ {28x}^{2} - 6x }$

Step-by-step explanation:

You would substitute "2x" for every "x" in the function in the same way you would substitute any other number.

So if f(x)=Sqrt[7x²-3x], then: f(2x)=Sqrt[7(2x)²-3(2x)]

=Sqrt[7(4x²)-3(2x)]

=Sqrt[28x²-6x]

6 0

3 years ago

show that any binary integer is at most four times as long as the corresponding decimal integer. for very large numbers, what is

makkiz [27]

It has been shown that any binary integer is at most four times as long as the corresponding decimal integer.

<h3>What is the binary code?</h3>

The binary code is a method of expressing numbers that makes use of one and zero. It is the method in which the computer encodes data. The data must be transformed into zeros and ones before they can be encoded.

For instance, the number 8 is (1000)2. This shows that any binary integer is at most four times as long as the corresponding decimal integer.

Learn more about binary integer:brainly.com/question/14866711

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4 0

1 year ago

The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s

Norma-Jean [14]

The positions when the particle reverses direction are:

$s(t_1)=55ft\\\\s(t_2)=28ft$

The acceleraton of the paticle when reverses direction is:

$a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}$

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

$s(t)=2t^{3}-21t^{2}+60t+3$

So,

- Derivating to get the velocity function, we have:

$v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60$

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

$v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s$

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

$a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42$

Now, substituting the times to calculate the accelerations, we have:

$a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}$

Now, substitutitng the times to calculate the positions, we have:

$s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft$

Have a nice day!

3 0

3 years ago