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disa [49]
3 years ago
14

X^2+15x=-45 solve by factoring

Mathematics
2 answers:
Julli [10]3 years ago
6 0

1 Move all terms to one side.

{x}^{2}+15x+45=0

x

2

+15x+45=0

2 Use the Quadratic Formula.

x=\frac{-15+3\sqrt{5}}{2},\frac{-15-3\sqrt{5}}{2}

x=

2

−15+3

5

,

2

−15−3

5

3 Simplify solutions.

x=-\frac{3(5-\sqrt{5})}{2},-\frac{3(5+\sqrt{5})}{2}

x=−

2

3(5−

5

)

,−

2

3(5+

5

)

harina [27]3 years ago
4 0

Answer:

x =  - \frac{15-3\sqrt{5} }{2}; - \frac{15+3\sqrt{5} }{2}

Step-by-step explanation:

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4 years ago
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monitta

Answer:

5.8

Step-by-step explanation:

To get the mean, add up all the numbers

9+4+8+3+5 = 29

Then divide by how many numbers there are (5)

29/5 =5.8

The mean is 5.8

4 0
4 years ago
Please help please just give meh an example
Brrunno [24]

Answer: A compound event is an event that has more than one possible outcomes.

Example: Outcome of rolling a 6 since the dice is 6 sided. 1/6 is the probability .

5 0
3 years ago
What value of $k$ will make $4x^2 - 20x + k$ the square of a binomial?
Arisa [49]

Answer:

k = 25

Step-by-step explanation:

(2x  - sqrt(k) )^2              Expand this as a binomial                          

4x^2 - 4x*sqrt(k) + k      The middle term must be -20x Solve for k so it is

-4xsqrt(k) = - 20x            Divide by -4x

sqrt(k) = -20x/-4x             Do the division

sqrt(k) = 5                         Square both sides

k = 25


5 0
3 years ago
One bar of candy A and two bars of candy B have 774 calories. Two bars of candy A and one bar of candy B contains 786 calories.
vampirchik [111]
◆ Define the variables:

Let the calorie content of Candy A = a
and the calorie content of Candy B = b

◆ Form the equations:

One bar of candy A and two bars of candy B have 774 calories. Thus:

a + 2b = 774

Two bars of candy A and one bar of candy B contains 786 calories

2a + b = 786

◆ Solve the equations:

From first equation,
a + 2b = 774
=> a = 774 - 2b

Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie

◆ Find caloric content:

Caloric content of candy B = 254 calorie

Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie
5 0
3 years ago
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