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rodikova [14]
3 years ago
11

The variance of the sample data is?

Mathematics
1 answer:
hammer [34]3 years ago
7 0

Answer:

12.4523 kg

Step-by-step explanation:

The variance is found by averaging the square of the deviance (how far a number is from the mean) of each number.

Since we found the average of the deviance, all we have to do now is square that, and divide by the number of subjects.

11.1590² = 124.5232 --> 124.5232/10 = 12.4523 kg

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If you could help I would really appreciate it, but if not that’s fine. Thank you.
zloy xaker [14]

Answer:

2x - 5 if x ≤ 2

f(-1) = -7

Step-by-step explanation:

x ≤ 2 = (-1) ≤ 2

x > 2 = (-1) > 2

2x - 5

2(-1) - 5

-2 - 5

-7

8 0
2 years ago
What is the solution of 5sin2θ=3 for 0≤θ≤2π? Please help.
grigory [225]

Answer:

C) \theta\approx\{0.3218,1.249,3.463,4.3908\}

Step-by-step explanation:

5\sin2\theta=3;\: 0\leq\theta\leq 2\pi\\\\\sin2\theta=\frac{3}{5}\\ \\2\theta\approx\{0.6436,2.498,6.926,8.7816\}\\\\\theta\approx\{0.3218,1.249,3.463,4.3908\}

7 0
2 years ago
Pl help it’s for a grade
allsm [11]

Answer:

(^6√x^5) (√y)

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For x the 6 moves to the front of the square root while the 5 becomes the power of x.

For y, the power to the 1/2 is the same as a square root.

5 0
2 years ago
Factor as the product of two binomials. x^2 + 3x +2
Sergio039 [100]
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In the Salk vaccine field trial, 400,000 children were part of a randomized controlled double-blind experiment. Just about half
EastWind [94]

Answer:

Step-by-step explanation:

From the given information:

The number of children that were randomly allocated to each vaccination group; n₁ = 200,000

No of polio cases X₁ = 57

Now, in the vaccine group:

the proportion of polio cases is:

\hat p_1 = \dfrac{57}{200000}

=  0.000285

The number of children that were randomly allocated to the placebo group, n₂ = 200,000

No of polio cases X₂ = 142

In the placebo group

the proportion of polio cases is:

\hat p_2 = \dfrac{142}{200000}

Null and alternative hypothesis is computed as follows:

H₀: There is no difference in the proportions of polio cases between both groups.  

H₁: There is a difference in the proportions of polio cases between both groups.

Let assume that the level of significance ∝ = 0.05

The test statistic  can be computed as:

Z = \dfrac{\hat p_1-\hat p_2}{\sqrt{\dfrac{\hat p_1 \hat q_1}{n_1}+ \dfrac{\hat p_2 \hat q_2}{n_2}}}

Z = \dfrac{0.000285-0.000710}{\sqrt{\dfrac{0.000285(1-0.000285)}{200000}+ \dfrac{0.000710(1-0.000710)}{200000}}}

Z = \dfrac{-4.25\times 10^{-4}}{\sqrt{\dfrac{0.000285(0.999715)}{200000}+ \dfrac{0.000710(0.99929)}{200000}}}

Z = - 6.03

P-value =  2P(Z < -6.03)

From the Z - tables

P-value =  2 × 0.0000

= 0.000

We reject the H₀ provided that P-value is very less.

Therefore, we may conclude that there is a difference in the proportions of polio cases between the vaccine group and placebo group not due to chance.

7 0
2 years ago
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