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yuradex [85]
2 years ago
6

Can you help me solve this please ​

Mathematics
1 answer:
OLga [1]2 years ago
8 0

Answer:

-22+27i

Step-by-step explanation:

i =  \sqrt{ - 1}  \\ (3 - 4i)( - 6 + i) \\  = (3 - 4 \sqrt{ - 1} )( - 6 +  \sqrt{ - 1} ) \\  = 3( - 6 +  \sqrt{ - 1)}  - 4 \sqrt{ - 1} ( - 6 +  \sqrt{ - 1} ) \\  =  - 18 + 3 \sqrt{ - 1}  + 24 \sqrt{ - 1}  - 4 \\  =  - 22 + 27 \sqrt{ - 1} \\ putting \:  \:  \:  \sqrt{ - 1 }  = i \\  =  - 22 + 27i

Hope it helps.

Don't forget to click the Brainliest button if you like my answer.

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<u>Tangent Line of a Function</u>

Given f(x) a real differentiable function in x=a, the slope of the tangent line of the function in x=a is given by f'(x=a). Where f' is the first derivative of f.

We are given

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