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2 years ago

What is -3(2x-4)+9x-8

Mathematics

1 answer:

professor190 [17]2 years ago

3 0

Answer:

3x+4

Step-by-step explanation:

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Help pls help plsssssss

densk [106]

Answer:

bro its 10

Step-by-step explanation:

5 kilometers in 30mins and if he stayed at the same rate for an hour he would have ran 10 kilometers cause 5 x 2 = 10

8 0

2 years ago

How many hours would it take Natalie if she worked alone?

Annette [7]

It would take Natalie 6 hours by herself since she will finish in twice the time if she had Caesar to help.

3 0

1 year ago

Help pleaseeeeeeeeeeeeeeee

kupik [55]

Answer:C

Step-by-step explanation:

your answer is 390

First area of the rectangle which formula is bxh base time height.

that gives you 300 since 15x20=300

The for the triangle Formula is Basexheight deivded by 2

so 15x12 devided by 2 =90

300+90=390

Hope this helps you. :)

8 0

2 years ago

An angle in standard position measures 5п 8 radians. In which quadrant does the terminal side of this angle lie? O Quadrant I II

user100 [1]

Answer:

I've attached a picture of a unit circle with the quadrant labeled.

Calculate the degree of 5п 8 radians:

$\frac{5\pi }{8} =\frac{5*180}{8} =\frac{900}{8} =112.5$

Locate the general location of 112.5° on the unit circle:

It's between 120°( $\frac{2\pi }{3}$ ) and 90°( $\frac{\pi }{2}$ ).

Find the quadrant it lies in:

Quadrant II

5 0

2 years ago

Which equations for the measures of the unknown

MAXImum [283]

Answer: Option B, Option C, Option E

Step-by-step explanation:

The options written correctly, are:

$A)x = cos^{-1}(\frac{a}{c})\\\\B) x = sin^{-1}(\frac{c}{b})\\\\C)x = tan^{-1}(\frac{c}{a})\\\\D) y = sin^{-1}(\frac{a}{c})\\\\ E)y = cos^{-1}(\frac{c}{b})$

For this exercise you need to use the following Inverse Trigonometric Functions:

$1)\ sin^{-1}(x)\\\\2)\ cos^{-1}(x)\\\\3)\ tan^{-1}(x)\\\\$

When you have a Right triangle (a triangle that has an angle that measures 90 degrees) and you know that lenght of two sides, you can use the Inverse Trigonometric Functions to find the measure of an angle $\alpha$ :

$1)\alpha = sin^{-1}(\frac{opposite}{hypotenuse}) \\\\2)\ \alpha =cos^{-1}(\frac{adjacent}{hypotenuse})\\\\3)\ \alpha=tan^{-1}(\frac{opposite}{adjacent})$

Therefore, the conclusion is that the angles "x" and "y" can be found with these equations:

$x=sin^{-1}(\frac{c}{b})\\\\x= cos^{-1}(\frac{a}{b})\\\\x=tan^{-1}(\frac{c}{a})\\\\\\ y=sin^{-1}(\frac{a}{b})\\\\y=cos^{-1}(\frac{c}{b})\\\\y=tan^{-1}(\frac{a}{c})$

5 0

3 years ago

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