The right answer is B.
Insertion is a genetic mutation characterized by the entrenchment of genetic material in a chromosome. The insertion size varies between a base pair and an entire sector of a chromosome moved to another. In the latter case, part of the genetic data of the first chromosome is erased. This can happen during an uneven jumping.
The embedding of nucleic bases in a gene makes it longer and shifts the reading of its data, which can modify its functioning in a harmful way, especially if the insertion occurs on the exon (fragments of an RNA primary presence in cytoplasmic RNA after splicing).
Answer:
- Lumen of duodenum will be acidic as compard to normal environment of the lumen of abdomen when processing a meal.
- Digestion of some foods will not be be adequate due to the bloackage of enzymes.
- Fat digestion will be decreased greatly because bile will be blocked too.
Explanation:
Breakdown of sugars and proteins occurs by the digestive juices secreted by the pancreas (pancreatic juice) while the bile duct is concenred with the emulsification of fats.
Highly alkaline bicarbonate juices are also produced and secreted by pancreas which raise the pH of the duodenum.
Thus, when both of them are absent, digestion of the food will be affected and becomes impaired and also causing the pH of duodenum to turn acidic. Also the bile salts, bilirubin and biliverd in the bile juice which are important for emulsification of fats and their consequent digestion.
Hence,
- Lumen of duodenum will be acidic as compard to normal environment of the lumen of abdomen when processing a meal.
- Digestion of some foods will not be be adequate due to the bloackage of enzymes.
- Fat digestion will be decreased greatly because bile will be blocked too.
O<u>n MAGIC analysis</u><u> it is found that reduced ubiquinone is being </u><u>accumulated </u><u>and c</u><u>omplex III</u><u> is oxidized. </u>
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Is Complex III reduced or oxidized?
Process - During each two-cycle process, the modified Q cycle in Complex III reduces cytochrome c, oxidizes ubiquinol to ubiquinone, and transfers four protons into the intermembrane gap.
Does ubiquinone get oxidized or reduced?
- At the cellular level, CoQ10 exists as a redox pair, or in two forms that alternate back .
- Forth as CoQ10 transfers a hydrogen in the mitochondria's electron transfer chain: ubiquinone, which is the oxidized form, and ubiquinol, which is the reduced form.
What is the function of complex III?
- The mitochondria of cells, which transform the energy from food into a form that cells can utilise, are where Complex III is found.
- Cells obtain a great deal of their energy from a process called oxidative phosphorylation, which is carried out by a number of complexes, including Complex III.
Learn more about Complex III.
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<u>The complete question is -</u>
We now get to the crux of the matter. If we are to identify which step is blocked, we will need at least two specific pieces of information.
Now let's put it all together . If you were told that ubiquinone was reduced but cytochrome c was oxidized , you would know that the pathway was blocked somewhere between these two carriers , but you would not necessarily know whether the block was at the ubiquinone ⇒ Complex lll step or the Complex III ⇒ cytochrome c step.
To differentiate between these two steps, you add an unknown inhibitor to a suspension of rapidly respiring mitochondria. After subjecting the suspension to MAGIC analysis, you find that there is an accumulation of reduced ubiquinone and that Complex III is oxidized.
Answer:
The correct answer is d. increases at a slower rate.
Explanation:
As the volume of a cell increases a cell grows bigger but unfortunately the surface area does do not increase as faster as the volume, therefore, the relative surface area amount which is available to pass the molecule across plasma membrane per unit volume decreases.
Therefore as the cell increase in size the surface area to volume ratio decreases. So if a cell grows more than its limit it will get difficult to move molecule fastly across its membrane. Therefore the correct answer is d.
Answer:
The answer should be
NaI→2Na+I2. :)