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Nadusha1986 [10]
3 years ago
6

Amy is helping plan her school's new basketball court. The west edge of the basketball court is located on the line y = 2x + 5.

The east edge cannot intersect with the west edge. On which line could the east edge be located?
Mathematics
1 answer:
lord [1]3 years ago
6 1

Answer:

Step-by-step explanation:

hello :

The east edge cannot intersect with the west edge so :

the west edge and The east edge are paralal same slope but the slope for the line y = 2x + 5 is : 2

so : the line could the east edge be located is : y= 2x+b b : no 5

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Please help me with this
m_a_m_a [10]

Explanation:

Steve correctly computed the change in x to be 2, and the change in y to be 6. However he put 2 in the slope formula for Δy (the change in y), and 6 for Δx. That is, Steve reversed the values of Δx and Δy.

The actual slope is ...

  slope = Δy/Δx = 6/2 = 3

7 0
3 years ago
What is the distance points for (2,-2) and (0,-9)
Ksivusya [100]

The distance between two points (2,-2) and (0,-9) is 7.3 units, which is obtained by graphical method and formula method.

Step-by-step explanation:

The given is,

         Two points are (2,-2) and (0,-9)

Step:1

         By graphical method,

         For two points (2,-2) and  (0,-9)

                  First point (2,-2)

                             The values of x=2 and y=-9 noted in the graph

                  Second point (0,-9)

                              The values of x=0 and y=-9 noted in the graph

                  Now join the two points, measure the distance between the two points,

                   Distance between points are 7.3 units.

                                          ( OR )

Step:1

        By formula method,

              Distance =   \sqrt{(x_{2}- x_{2})  ^{2}+ (y_{2}-y_{1})  ^{2}  }

       Where,

               ( 2,-2) are (x_{1},y_{1})

               (0,-9) are (x_{2},y_{2})

       From the values,

                             = \sqrt{(0- 2)  ^{2}+ (-9+2)  ^{2}  }

                            =  \sqrt{(- 2)  ^{2}+ (-7)  ^{2}  }

                            = \sqrt{4+49  }

                            = \sqrt{53}

                            = 7.280

                            ≅ 7.3

            Distance = 7.3

Result:

           The distance between two points (2,-2) and (0,-9) is 7.3 units, which is obtained by graphical method and formula method.

5 0
3 years ago
I need y’all to help me asap!!!!!!
timofeeve [1]

Answer:

-1

Step-by-step explanation:

f(0) = -5^0 = -1

8 0
3 years ago
What is the value of x?
hammer [34]

Answer:

16.

How to find... ↓

The small triangle is 1/3 size of the big triangle.

If this is the case, find the LCF here, 4, and multiply each angle's value by the least common factor, 4.

3 x 4 (bottom) = 12

5 x 4 (right side) = 20

4 x 4 (left side <em>the missing side) </em>= 16

Therefore,

The missing side value, <em>x</em>, is 16.

6 0
2 years ago
Read 2 more answers
Ten experts rated a newly developed chocolate chip cookie on a scale of 1 to 50. Their ratings were: 34, 35, 41, 28, 26, 29, 32,
miskamm [114]

The mean deviation of the ratings is  4.12

<em><u>Explanation</u></em>

The ratings of the ten experts are:  34, 35, 41, 28, 26, 29, 32, 36, 38 and 40

So, the mean of all ratings =\frac{34+35+41+28+26+29+32+36+38+40}{10}= \frac{339}{10}=33.9

<u>The formula for Mean deviation</u> = \sum \frac{|x_{i}- \mu|}{N} , where x_{i} is the given data from i=1 to i=10 , \mu is the mean of the data and N is the total number of data. So.....

|x_{1}-\mu |= |34-33.9|=0.1\\ |x_{2}-\mu|=|35-33.9|=1.1\\ |x_{3}-\mu |=|41-33.9|=7.1\\ |x_{4}-\mu |=|28-33.9|=5.9\\ |x_{5}-\mu |=|26-33.9|=7.9\\ |x_{6}-\mu |=|29-33.9|=4.9\\|x_{7}-\mu |=|32-33.9|=1.9\\ |x_{8}-\mu |=|36-33.9|=2.1\\ |x_{9}-\mu |=|38-33.9|=4.1\\ |x_{10}-\mu |=|40-33.9|=6.1

So, the Mean deviation =\sum \frac{|x_{i}-\mu |}{N}=\frac{0.1+1.1+7.1+5.9+7.9+4.9+1.9+2.1+4.1+6.1}{10} = \frac{41.2}{10}=4.12

4 0
4 years ago
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