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Nadusha1986 [10]
3 years ago
6

Amy is helping plan her school's new basketball court. The west edge of the basketball court is located on the line y = 2x + 5.

The east edge cannot intersect with the west edge. On which line could the east edge be located?
Mathematics
1 answer:
lord [1]3 years ago
6 1

Answer:

Step-by-step explanation:

hello :

The east edge cannot intersect with the west edge so :

the west edge and The east edge are paralal same slope but the slope for the line y = 2x + 5 is : 2

so : the line could the east edge be located is : y= 2x+b b : no 5

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Which is the graph of f(x)= 3 sq root -x?
sattari [20]

Answer:

3rd option. The way you do it is just plug in negative x value let's say -8, plug it in then y would be a positive value. So that rules out first two options. Then plug in positive x value, y would be negative.

8 0
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SECUL
dmitriy555 [2]
Answer:
he bought 5 english books and 5 math books

explanation:
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4 0
3 years ago
(15a -7b+4c) -(-3a-6b+12c) adalah​
Firlakuza [10]

Answer:

15a-7b+4c+3a+6b-12c

=18a-b-8c

8 0
3 years ago
6) Two coastguard stations P and Q are 17km apart, with due East of P. A ship S is observed in distress on a bearing 048° fromP
adelina 88 [10]

Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = 360^{o} - 324^{o}

     = 036^{o}

Sum of angles in a triangle = 180^{o}

<P + <Q + <S = 180^{o}

048° + 036^{o} + <S = 180^{o}

84^{o} + <S = 180^{o}

<S  = 180^{o} -  84^{o}

    = 96^{o}

<S = 96^{o}

Applying the Sine rule,

\frac{y}{Sin P} = \frac{x}{Sin Q} = \frac{z}{Sin S}

\frac{y}{Sin P} = \frac{z}{Sin S}

\frac{y}{Sin 48^{o} } = \frac{17}{Sin 96^{o} }

\frac{y}{0.74314} = \frac{17}{0.99452}

⇒ y = \frac{12.63338}{0.99452}

       = 12.703

y = 12.70 km

\frac{x}{Sin Q} = \frac{z}{Sin S}

\frac{x}{Sin 36^{o} } = \frac{17}{Sin 96^{o} }

\frac{x}{0.58779} = \frac{17}{0.99452}

⇒ x = \frac{9.992430}{0.99452}

      = 10.0475

x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

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Just add up all the numbers and divide by 6, as there are six numbers in this set of numbers
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