C. camouflage, camouflage is when an animal is blending in with its surroundings.
Answer:
2,855 is the size of the colony of mosquitoes after 4 days.
Explanation:
The law of uninhibited growth is given as:
![A=A_o\times e^{k\times t}](https://tex.z-dn.net/?f=A%3DA_o%5Ctimes%20e%5E%7Bk%5Ctimes%20t%7D)
= Original amount
A = Amount after time t
k = Positive constant repressing the rate of growth
We are given with:
Original population of mosquitoes = 1000
Population of mosquitoes after 1 day =1300
t = 1 day
![1300=1000\times e^{k\times 1 day}](https://tex.z-dn.net/?f=1300%3D1000%5Ctimes%20e%5E%7Bk%5Ctimes%201%20day%7D)
![k = 0.2623 day^{-1}](https://tex.z-dn.net/?f=k%20%3D%200.2623%20day%5E%7B-1%7D)
Population size of mosquitoes after 4 days
![A_o=1000, k= 0.2623 day^{-1}](https://tex.z-dn.net/?f=A_o%3D1000%2C%20k%3D%200.2623%20day%5E%7B-1%7D)
A =? , t = 4 days
![A=1000\times e^{ 0.2623 day^{-1}\times 4 days}](https://tex.z-dn.net/?f=A%3D1000%5Ctimes%20e%5E%7B%200.2623%20day%5E%7B-1%7D%5Ctimes%204%20days%7D)
A =2,855.36 ≈ 2,855 mosquitoes
2,855 is the size of the colony of mosquitoes after 4 days.
The probability of transmitting both traits to his son is Zero. This is because the son has one X chromosome and one Y chromosome (XX), therefore since the traits are linked to the X chromosomes, it means the son will only be a carrier but will not show the trait phenotypically.