Question

Someone please answer this! THANKSSSS

Answer 1

Answer:

in right angled triangle MNO

relationship between base and hypotenuse is given by cos angle

cosx°=b/h

cosx°=OM/MN

x°=cos-1(26/99)=74.77=74.8°

Answer 2

Answer:

∠ M ≈ 74.8°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos M = $\frac{adjacent}{hypotenuse}$ = $\frac{OM}{MN}$ = $\frac{26}{99}$ , then

∠ M = $cos^{-1}$ ($\frac{26}{99}$ ) ≈ 74.8° ( to the nearest tenth )