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Kobotan [32]
3 years ago
15

Someone please answer this! THANKSSSS

Mathematics
2 answers:
iren2701 [21]3 years ago
8 0

Answer:

in right angled triangle MNO

relationship between base and hypotenuse is given by cos angle

cosx°=b/h

cosx°=OM/MN

x°=cos-1(26/99)=74.77=74.8°

vesna_86 [32]3 years ago
6 0

Answer:

∠ M ≈ 74.8°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos M = \frac{adjacent}{hypotenuse} = \frac{OM}{MN} = \frac{26}{99} , then

∠ M = cos^{-1} (\frac{26}{99} ) ≈ 74.8° ( to the nearest tenth )

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___ x 4 = 12<br> ___ x 5 = 20<br> ___ x 2 = 10
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Answer:

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Step-by-step explanation:

3 + 3 + 3 + 3 = 12

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3 years ago
Find the missing measure for a right circular cone TA is 12 pi and LA is 8 pi
salantis [7]

Answer:

The radius of the base of the cone is 2 units

The slant height of the cone is 4 units

The height of the cone is 2√3 units

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Step-by-step explanation:

* Lets revise the total surface area and the lateral area of a cone

- The lateral area of cone = π r l , where r is the radius of the base

  and l is the slant height of the cone

- The surface area of the cone = π r l + π r², where π r l is the lateral

  area and π r² is the base area

- The cone has three dimensions radius (r) , height (h) , slant height (l)

- r , h , l formed right triangle, r , h are its legs and l is its hypotenuse,

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- The volume of the con = \frac{1}{3} (π r² h)

* Now lets solve the problem

- We will use the total area to find the radius of the base

∵ TA = 12π

∵ TA = LA + πr²

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- Substitute the value of the lateral area in the total area

∴ 12π = 8π + π r² ⇒ subtract 8π from both sides

∴ 12π - 8π = π r²

∴ 4π = π r² ⇒ divide both sides by π

∴ r² = 4 ⇒ take square root for both sides

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* The radius of the base of the cone is 2 units

- We will use the lateral area to find the slant height

∵ LA = π r l

∵ LA = 8π

∵ r = 2

∴ π (2) l = 8π ⇒ divide both sides by π

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* The slant height of the cone is 4 units

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∵ r = 2 and l = 4

∵ l² = r² + h²

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∵ r = 2 and h = 2√3

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∴ V = \frac{8\sqrt{3}\pi}{3}

* The volume of the cone is \frac{8\sqrt{3}\pi}{3}units³

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