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Sophie [7]
3 years ago
15

A 35-m tall building casts a shadow. The distance from the top of the building to the tip of the shadow is 38 m . Find the lengt

h of the shadow. If necessary, round your answer to the nearest tenth.
Mathematics
2 answers:
ivolga24 [154]3 years ago
8 0
14.7-M  is the correct answer. Your welcome
kakasveta [241]3 years ago
3 0
Hello!

It seems like the building, shadow, and distance between the top of the building to the top of the shadow makes a triangle. It seems as if the shadow and building are two legs, and the tip distance is the hypotenuse.

With this problem we will use the Pythagorean Theorem, where a squared plus b squared equals c squared.

When our hypotenuse represents c, we will subtract rather than add as we already know the length of c. We need to find the length of the shadow, or leg.

We will square the numbers and subtract. Then we will find the square root of our result, giving us our answer.

1444-1225=219
The square root of 219 is about 14.8.

Just to check, let’s plug our a value into the Pythagorean theorem.

219.04+1225= 1444.04
The square root of 1444.04 is about 38, which is the length of our hypotenuse.

The length of the shadow was 14.8 meters long.

I hope this helps!
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A scientist had 3 1/2 liters of vinegar. He poured 2/3 of the vinegar into beaker. He then used 3/5 of the vinegar in the beaker
valentinak56 [21]

Answer:

A)2100 ml

Step-by-step explanation:

Given total vinegar is 3 1/2 liters and the used vinegar is  3/5 of the vinegar in the beaker:

#First calculate the amount of vinegar not poured in the beaker:

V_o=V_t-V_b\\\\=3\frac{1}{2}(1-\frac{2}{3})\\\\=1\frac{1}{6}

#Calculate amount of vinegar used in experiment:

V_b=\frac{2}{3}V_t=\frac{2}{3}(3\frac{1}{2})=2\frac{1}{3}\\\\V_u=\frac{3}{5}V_b=\frac{3}{5}\times 2\frac{1}{3}=1\frac{2}{5}

#The unused vinegar is therefore calculated by subtracting the used vinegar from the total at the start of the experiment:

V_r=V_t-V_u\\\\=3\frac{1}{2}-1\frac{2}5}\\\\=2\frac{1}{10}\times 1000\ ml\\\\=2100\ ml

Hence, the unused vinegar is 2100 ml

8 0
3 years ago
If f(x) = [xl-5, what is f(8.6)?
Fynjy0 [20]

Answer:

  3 or 4, depending on the intended meaning of [x]

Step-by-step explanation:

Perhaps you mean ...

  \displaystyle f(x)= \lfloor x\rfloor -5\\\\f(8.6)=\lfloor 8.6\rfloor-5=8-5=3

__

On the other hand, perhaps you mean ...

  \displaystyle f(x)=\lceil x\rceil -5\\\\f(8.6)=\lceil 8.6\rceil-5=9-5=4

4 0
3 years ago
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Nutka1998 [239]

Answer:

m = -2

Step-by-step explanation:

To get the slope of the line, we are going to use the 2-points slope equation form

That will be;

m = (y2-y1)/(x2-x1)

(x1,y1) = (-5,11)

(x2,y2) = (8,-15)

m = (-15-11)/(8-(-5)) = -26/13 = -2

The possible mistake she might have made is placing the x-values difference over the y and her formula will look like;

m = (x2-x1)/(y2-y1)

It is an error of switching the numerator for the denominator

5 0
3 years ago
Graphs of functions on the interval [−4, 4] are depicted below. For each function, find:
DENIUS [597]

Answer:

a) The domain is the set of the possible values of x.

In the graph, we can see that x goes from - 4 to 4

So the domain is: D = x∈ {-4, 4)

b) The zeros are the points where the graph cuts the x-axis.

Those values are:

x = -2

x = 0

x = 2.

c) The graph is positive if it is above the x-axis and it is negative if it is below the x-axis.

in the interval {-4,0} the graph is bellow the x-axis, so in this interval the function is negative.

in the interval {0, 2} the graph is above the x-axis, so in this interval the function is positive.

in the interval {2, 4} the graph is bellow the x-axis, so in this interval the function is negative.

4 0
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0.03is 10 times as much as
PSYCHO15rus [73]

Answer:

0.03 is 10 times as much as 0.003

Step-by-step explanation:

its the answer

8 0
2 years ago
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