Please help me find the solution!!!!

Math:<br> Please help me I don’t understand and I need to do corrections.

GREYUIT [131]

So, you had done everything right so far (other than squaring the 2), but that was only half of the question.

to find the least common multiple, you need to first figure out what the prime factors have in common.
${2}^{2} \times 3 \times 5 \\ and \\ {2}^{2} \times {3}^{2} \times 5 \times 7$
each have two twos. both have one 5, so we know our answer will look something like
${2}^{2} \times 5 \times other \: stuff$
now to figure out the other stuff... we have to represent the greatest amount of everything that is left, and we have 3s and 7s left over, so we need to figure out how many of each we need.

one has one 3 and one has two, so we need two threes. now our equation is
${2}^{2} \times {3}^{2} \times 5 \times stuff$

what's the only number we have to deal with? 7...

how many sevens does 60 have? 0, and 630 has 1, so we know we need one 7. our answer becomes

4 0

3 years ago

You deposit $175 in an account that pays 4% interest compounded quarterly. How much will you have in the account after 2 years?

melomori [17]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$175\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four times} \end{array}\dotfill &4\\ t=years\dotfill &2 \end{cases}$

$\bf A=175\left(1+\frac{0.04}{4}\right)^{4\cdot 2}\implies A=175(1.01)^8\implies A\approx 189.50$

6 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%285%5E%7B3%7D%29%5E%7B-3%7D" id="TexFormula1" title="(5^{3})^{-3}" alt="(5^{3})^{-3}" align="

morpeh [17]

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

$( { {5}^{3} })^{ - 3} \\ \\ which\:means \:that \: {5}^{3}\: is \:multiplied \:thrice\: with\: itself\\ \\ = {5}^{3 \times - 3} \\ \\ = {5}^{ - 9} \\ \\= \frac{1}{ {5}^{9} } \\ \\ = \frac{1}{5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5} \\ \\ = \frac{1}{1953125}$

<u>Note</u>:-

$( { {a}^{m} })^{n} = {a}^{m \times n}$

${a}^{ - m} = \frac{1}{ {a}^{m} }$

$\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}$

4 0

2 years ago

Why do whole numbers rise to an exponent get greater while fractions raise to an exponent get smaller?

erma4kov [3.2K]

Answer:

This is because exponents increase a number, for example $2, and, 2^2$ <em>squaring a number is basically multiplying it by itself.</em> So $2 * 2 = 2^2=4$ . Now obiviously 4 is greater than 2. But lets make the numbers like this: