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galina1969 [7]
3 years ago
12

How are using graphs equations and tables similar when distinguishing between proportional and nonproportional linear relationsh

ips?
Mathematics
1 answer:
MrMuchimi3 years ago
6 0
When using graphs to find proportional and nonproportional is easy. When it's proportional it goes right through the origin and it's nonproportional it doesn't go through the origin.
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I need to find the measure of the exterior angle of the triangle ​
ankoles [38]

Answer:

92º

Step-by-step explanation:

(2x-2)º=x+45º

2x-2=x+45

2x-x=45+2

x=47

____________

22x-2=2(47)-2=92º

6 0
2 years ago
PLEASE help. I have posted this question many times and no one is answering.
11111nata11111 [884]

Answer:

Proportional

Step-by-step explanation:

It follows the proportion of 1:10, 1 part bleach to 10 parts water.

3 0
3 years ago
A line passes through the point (0, –1) and has a slope of -2/3. What is the equation of the line?
sesenic [268]

y=-2/3x-1

is the equation

5 0
3 years ago
Read 2 more answers
in a given year, the rate of flu infection for the general public was 8.3%. And sample of 200 people who receive the flu vaccine
makkiz [27]

Answer:

\fbox{\begin{minipage}{10em}Option A is correct\end{minipage}}

Step-by-step explanation:

<em>Step 1: Define significance level</em>

In this hypothesis testing problem, significance levels α is selected: 0.05, the associated z-value from Laplace table:

Φ(z) = α - 0.5 = 0.05 - 0.5 = -0.45

=> z = -1.645

<em>Step 2: Define null hypothesis (</em>H_{0}<em>) and alternative hypothesis (</em>H_{1}<em>)</em>

H_{0} : rate of flu infection p = 8.3% or 8.3/100 = 0.083

H_{1} : rate of flu infection p < 8.3% or 8.3/100 = 0.083

<em>Step 3: Apply the formula to check test statistic:</em>

K = \frac{f - p}{\sqrt{p(1 - p)} } * \sqrt{n}

with f is actual sampling percent, p is rate of flu infection of H_{0}, n is number of samples.

The null hypothesis will be rejected if K < z

<em>Step 4: Calculate the value of K and compare with </em>z

K = \frac{(\frac{3.5}{100})  - 0.083}{\sqrt{0.083(1 - 0.083)} } * \sqrt{200} = -2.46  

We have -2.46 < -1.645

=>This is good evidence to reject null hypothesis.

=> The actual rate is lower. (As H_{1} states)

Hope this helps!

:)

5 0
3 years ago
your total savings varies inversely with the amount spent on Bill's. if your savings is $300 when your cost of Bill's are $65. W
tatyana61 [14]
Let S and B be savings and bills respectively. Then,
S α 1/B
S = k/B Where k = Constant.
When S = $300, B = 65

Then,
300 = k/65
k = 300*65 = 19500

Therefore,
For B = $145,

S= 19500/145 = $134.48
6 0
3 years ago
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