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statuscvo [17]
3 years ago
13

A plan for an executive traveler's club has been developed by an airline on the premise that at least 5% of its current customer

s would qualify for membership. A random sample of 500 customers yielded 40 who would qualify. Using this proportion data, test at alpha = .01 the null hypothesis that the company's premise is correct, against the alternative that it is higher than the premise. 1. What is the standard error for this hypothesis test?Use four decimal places in your answer and use the proper rules of rounding. 2. What is the critical value for this test?Use four decimal places in your answer and use the proper rules of rounding.

Mathematics
1 answer:
STatiana [176]3 years ago
7 0

Answer:

a) 3.0779

b)2.3264

Step-by-step explanation:

Please see attachment .

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Help loll i need an 100
vlabodo [156]

Answer:

-4 (as - and + = -)

Step-by-step explanation:

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3 years ago
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To the nearest whole degree, what angle measure has a sine of 0.3535? SOMEBODY HELP
Bas_tet [7]
The angle is sin inverse 0.3535 which is around 21 degrees
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3 years ago
The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.
andrezito [222]

Answer:

Given the equation: 3x^2+10x+c =0

A quadratic equation is in the form: ax^2+bx+c = 0 where a, b ,c are the coefficient and a≠0 then the solution is given by :

x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a} ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}

Simplify:

x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}

Also, it is given that the difference of two roots of the given equation is 4\frac{2}{3} = \frac{14}{3}

i.e,

x_1 -x_2 = \frac{14}{3}

Here,

x_1 = \frac{-10 + \sqrt{100- 12c}}{6} ,     ......[2]

x_2= \frac{-10 - \sqrt{100- 12c}}{6}       .....[3]

then;

\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}

simplify:

\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}

or

\sqrt{100- 12c} = 14

Squaring both sides we get;

100-12c = 196

Subtract 100 from both sides, we get

100-12c -100= 196-100

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve x_1 , x_2

x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}

or

x_1 = \frac{-10 + \sqrt{100- 96}}{6} or

x_1 = \frac{-10 + \sqrt{4}}{6}

Simplify:

x_1 = \frac{-4}{3}

Now, to solve for x_2 ;

x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}

or

x_2 = \frac{-10 - \sqrt{100- 96}}{6} or

x_2 = \frac{-10 - \sqrt{4}}{6}

Simplify:

x_2 = -2

therefore, the solution for the given equation is: -\frac{4}{3} and -2.


3 0
3 years ago
The set of all positive integers that are divisible by both 15 and 35 is infinite. What is the least positive integer in this se
solniwko [45]

Answer:

105

Step-by-step explanation:

A "set" is a group of numbers.

A "positive integer" is a whole number that's bigger than zero.

"divisible by both 15 and 35" means a number that 15 and 35 goes into (with no remainder)

"least" means smallest.

15 and 35 both go into 105.

3 0
2 years ago
Geometric series plato3ei=1(4x(1/2)i-1)
maw [93]

Answer:

i=1

Step-by-step explanation:

i=(4*(1/2)i-1)

i=2i-1

i=1

4 0
3 years ago
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