The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.
So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11) one by one.
f(1)=-6(1)+11=5 f(2)=-6(2)+11= -1 f(3)=-6(3)+11= -7 f(4)=-6(4)+11= -13 f(5)=-6(5)+11= -19 f(6)=-6(6)+11= -25 f(7)=-6(7)+11= -31 f(8)=-6(8)+11= -37 As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.
Given 2 secants from an external point to the circle.
Then the product of the external part and the whole of one secant is equal to the product of the external part and the whole of the other secant, that is
6(6 + y) = 5(5 + 16)
36 + 6y = 5 × 21 = 105 ( subtract 36 from both sides )
