The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.
So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11) one by one.
f(1)=-6(1)+11=5 f(2)=-6(2)+11= -1 f(3)=-6(3)+11= -7 f(4)=-6(4)+11= -13 f(5)=-6(5)+11= -19 f(6)=-6(6)+11= -25 f(7)=-6(7)+11= -31 f(8)=-6(8)+11= -37 As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.
If A is in Quadrant IV then the "opposite side" is negative and the "adjacent side" is positive. Since sec A = hyp / adj = 13 / 5 and since opp^2 + adj^2 must add up to hyp^2, Therefore y = √(hyp^2 - adj^2), or
