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vazorg [7]
3 years ago
7

At the instant the traffic light turns green, an automobile starts with a constant acceleration a of 2.70 m/s2. At the same inst

ant a truck, traveling with a constant speed of 9.50 m/s, overtakes and passes the automobile. (a) How far beyond the traffic signal will the automobile overtake the truck
Physics
1 answer:
kifflom [539]3 years ago
3 0

Answer:

66.85 m

Explanation:

We are given that

Acceleration ,a=2.7m/s^2

Speed of truck, v=9.5 m/s

We have to find the distance beyond which the traffic signal will the automobile overtake the truck.

Initial speed of automobile, u=0

We know that

s=ut+\frac{1}{2}at^2

Using the formula

s=0+\frac{1}{2}(27)t^2=\frac{27}{2}t^2

For constant speed

Acceleration, a=0

Again

s=vt+0=9.5t

9.5t=\frac{27}{2}t^2

t=\frac{9.5\times 2}{2.7}=7.037s

Substitute the value of t

x=9.5(7.037)=66.85m

Hence, the distance beyond which the traffic signal will the automobile overtake the truck=66.85 m

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A motorbike accelerates from 15m/s to 25m/s in 15 seconds.
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3 years ago
A satellite that goes around the earth once every 24 hours iscalled a geosynchronous satellite. If a geosynchronoussatellite is
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Answer:

R=4.22*10⁴km

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R=\sqrt[3]{\frac{(6.67*10^{-11}Nm^{2}/kg^{2})(5.97*10^{24}kg)(86400s)^{2}}{4\pi^{2}}}\\\\R=4.22*10^{7}m=4.22*10^{4}km

This means that the radius of the orbit of a geosynchronous satellite that circles the earth is 4.22*10⁴km.

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