Answer:
Explanation:
The mass of the deuteron = mass of the proton + mass of the neutron + mass equivalent of the energy of 2.2 Mev evolved.
I amu = 931 Mev
2.2 Mev = 2.2 / 931 amu
= ( 2.2 / 931 )x 1.6726 x 10⁻²⁷
= .00395 x 10⁻²⁷
The mass of the deuteron =( 1.6726 + 1.6749 + .00395)x 10⁻²⁷ kg
= 3.35145 x 10⁻²⁷ kg
b ) Momentum of gamma ray
= h / λ ( h is plank's constant and λ is wavelength of gamma ray )
= hυ / υλ ( υ is frequency of gamma ray )
= E / c ( E is energy of photon and c is velocity o light )
= 2.2 x 10⁶ x 1.6 x 10⁻¹⁹ J / 3 x 10⁸
= 1.173 x 10⁻²¹ Kg m /s
This will be the momentum of deuteron also
Kinetic energy
= p² / 2m ( p is momentum and m is mass of deuteron )
= ( 1.173 x 10⁻²¹ )² / ( 2 x 3.35145 x 10⁻²⁷)
= 1.376 x ⁻¹⁵ J
Energy of gamma ray
= 2.2 x 10⁶ x 1.6 x 10⁻¹⁹ J
= 3.52 x 10⁻¹³ J
So kinetic energy of deuteron is smaller than energy of gamma ray photon .
The dummy's acceleration is 11 m/s^2
(also known as 11 meters per sec. per sec.)
a = F/m
= 825 N/75 kg
= 11 m/s^2
let the length of the beam be "L"
from the diagram
AD = length of beam = L
AC = CD = AD/2 = L/2
BC = AC - AB = (L/2) - 1.10
BD = AD - AB = L - 1.10
m = mass of beam = 20 kg
m₁ = mass of child on left end = 30 kg
m₂ = mass of child on right end = 40 kg
using equilibrium of torque about B
(m₁ g) (AB) = (mg) (BC) + (m₂ g) (BD)
30 (1.10) = (20) ((L/2) - 1.10) + (40) (L - 1.10)
L = 1.98 m
Answer:
It must return at the same velocity with which it was thrown or else there would be a preferred direction of motion leading to perpetual motion.
a = (v2 - v1) / t = (v2 - 0) / 2 = v2 / 2 for a falling object
v2 = 2 a = 2 sec * 9.8 m/sec^2 = 19.6 m/s
You can check with
H = V0 t - 1/2 g t^2 (V0 and g are in different directions)
H = 0
V0 = 1/2 g * 4 = 19.6 m/s