Answer:
H = 1/2 g t^2 where t is time to fall a height H
H = 1/8 g T^2 where T is total time in air (2 t = T)
R = V T cos θ horizontal range
3/4 g T^2 = V T cos θ 6 H = R given in problem
cos θ = 3 g T / (4 V) (I)
Now t = V sin θ / g time for projectile to fall from max height
T = 2 V sin θ / g
T / V = 2 sin θ / g
cos θ = 3 g / 4 (T / V) from (I)
cos θ = 3 g / 4 * 2 sin V / g = 6 / 4 sin θ
tan θ = 2/3
θ = 33.7 deg
As a check- let V = 100 m/s
Vx = 100 cos 33.7 = 83,2
Vy = 100 sin 33,7 = 55.5
T = 2 * 55.5 / 9.8 = 11.3 sec
H = 1/2 * 9.8 * (11.3 / 2)^2 = 156
R = 83.2 * 11.3 = 932
R / H = 932 / 156 = 5.97 6 within rounding
<span>The plates make up Earth's outer shell, called the lithosphere. (This includes the crust and uppermost part of the mantle.) Churning currents in the molten rocks below propel them along like a jumble of conveyor belts in disrepair. Most geologic activity stems from the interplay where the plates meet or divide.</span>
To solve this problem it is necessary to apply the concepts related to hydrostatic pressure or pressure due to a fluid.
Mathematically this pressure is given under the formula

Where,
= Density
h = Height
g = Gravitational acceleration
Rearranging in terms of g

our values are given as



Replacing we have


Therefore the gravitational acceleration on the planet's surface is
(Almost the gravity of the Earth)
Explanation:
goood and mark this answer as brainliest
I did try to solve. I hope it is correct, below is the solution:
<span>put everything in s.i units
then the answer what u wrote is acceleration to get is divide by mass(80)
G=6.011*10^-11
M=6*10^24
R=6.4*10^6
m=80
</span>
Hope it helps.