Question

URGENT!!!! WILL GIVE BRAINLIEST TO FIRST RIGHT ANSWER!!!!!!

Answer 1

geometric sequence

$\tt U_n=ar^{n-1}$

a = 6 = first term

r = ratio = $\tt \dfrac{9}{6}$

the 6th term (n=6)

$\tt U_6=6\times (\dfrac{9}{6})^{6-1}\\\\U_6=6\times \dfrac{9}{6}^5\\\\U_6=\dfrac{9^5}{6^4}=45.5625\rightarrow rounded~to nearest~thousandth=45.563$