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3 years ago

5 points

Mathematics

1 answer:

kifflom [539]3 years ago

7 0

Answer:

y = - 10/3 + 70

Step-by-step explanation:

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What proportion of students are willing to report cheating by other students? A project put this question to an SRS of 180 under

krok68 [10]

Answer:

13.89% of students are willing to report cheating by other students.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 180

Number of students who reported cheating, x = 25

We have to find the proportion of the students are willing to report cheating by other students.

Proportion of students can be calculate as

$p = \dfrac{x}{n} = \dfrac{25}{180} = 0.1389\\\\\p = 0.1389\times 100\5\\p = 13.89\%$

Thus, 13.89% of students are willing to report cheating by other students.

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3 years ago

What is 123 as a percent????

Anarel [89]

Answer:

12,300%

Step-by-step explanation:

7 0

3 years ago

PLEASE HELP ME I BEG

Kay [80]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

• 1 + cot²x = csc²x

Consider the left side

$csc^{4}$ x - $cot^{4}$ x

Factorise as a difference of squares

= (csc²x - cot²x)(csc²x + cot²x)

= (1 + cot²x - cot²x)(csc²x + cot²x)

= csc²x + cot²x

= csc²x + csc²x - 1

= 2csc²x - 1 = right side ⇒ verified

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3 years ago

If sin(theta) =4/5 and is in quadrant 2, the value of cot(theta

iren [92.7K]

$\sin\theta= \frac{4}{5} 
\\
\\\sin^2\theta+\cos^2\theta=1
\\ \cos\theta=\pm \sqrt{1-\sin^2\theta} =\pm \sqrt{1-( \frac{4}{5})^2 } =\pm \sqrt{1- \frac{16}{25} } =\pm \sqrt{\frac{9}{25} }=\pm \frac{3}{5}}$

$\theta \in II \Rightarrow \cos\theta\ \textless \ 0 \Rightarrow \cos\theta=-\frac{3}{5}$

$\cot\theta= \frac{\cos\theta}{\sin\theta}= \frac{-\frac{3}{5}}{\frac{4}{5}} =- \frac{3}{4}$

5 0

3 years ago

PLZZZZZZZZZZZZ help asap no links please

Blizzard [7]

If you show the menu I can help

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3 years ago

Read 2 more answers