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Tcecarenko [31]
3 years ago
11

Help a guy/girl/non-binary out? Please?

Mathematics
1 answer:
klemol [59]3 years ago
5 0

Answer:

72

Step-by-step explanation:

For Q 1 : 25 % of the scores are below this value. The area under the bell-shaped curve of the normal distribution is 0.25. And since we have 288 electricians that took a certification test:

0.25 * 288 = 72.

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Can someone please help I can’t understanddd.
dem82 [27]

Hello,

Dividing by 0 is not defined so let s take x different from 4 and -4 and then we can write:

As

f(x)=x^2-7x+12=x^2-4x-3x+12=x(x-4)-3(x-4)=(x-4)(x-3)\\ \\(f\times g)(x)=\dfrac{3(x-4)(x-3)}{(x-4)(x+4)}=\dfrac{3x-9}{x+4}

Thanks

6 0
3 years ago
Solve the equation :<br>-3 • ( 2 - x ) + 4 = 2 • ( 1 - 2x) + 3<br>thanks :) ​
kakasveta [241]

Isolate the variable by dividing each side by factors that don't contain the variable.

x  =  1

-6+3x+4=2-4x+3

-8+7x+1=0

7x=7

x=1

4 0
3 years ago
The coordinates of rhombus ABCD are A(–4, –2), B(–2, 6), C(6, 8), and D(4, 0). What is the area of the rhombus? Round to the nea
a_sh-v [17]
Check the picture below.

so the rhombus has the diagonals of AC and BD, now keeping in mind that the diagonals bisect each, namely they cut each other in two equal halves, let's find the length of each.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-2})\qquad &#10;C(\stackrel{x_2}{6}~,~\stackrel{y_2}{8})\qquad \qquad &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;AC=\sqrt{[6-(-4)]^2+[8-(-2)]^2}\implies AC=\sqrt{(6+4)^2+(8+2)^2}&#10;\\\\\\&#10;AC=\sqrt{10^2+10^2}\implies AC=\sqrt{10^2(2)}\implies \boxed{AC=10\sqrt{2}}\\\\&#10;-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;B(\stackrel{x_1}{-2}~,~\stackrel{y_1}{6})\qquad &#10;D(\stackrel{x_2}{4}~,~\stackrel{y_2}{0})\qquad \qquad BD=\sqrt{[4-(-2)]^2+[0-6]^2}&#10;\\\\\\&#10;BD=\sqrt{(4+2)^2+(-6)^2}\implies BD=\sqrt{6^2+6^2}&#10;\\\\\\&#10;BD=\sqrt{6^2(2)}\implies \boxed{BD=6\sqrt{2}}

that simply means that each triangle has a side that is half of 10√2 and another side that's half of 6√2.

namely, each triangle has a "base" of 3√2, and a "height" of 5√2, keeping in mind that all triangles are congruent, then their area is,

\bf \stackrel{\textit{area of the four congruent triangles}}{4\left[ \cfrac{1}{2}(3\sqrt{2})(5\sqrt{2}) \right]\implies 4\left[ \cfrac{1}{2}(15\cdot (\sqrt{2})^2) \right]}\implies 4\left[ \cfrac{1}{2}(15\cdot 2) \right]&#10;\\\\\\&#10;4[15]\implies 60

7 0
3 years ago
Read 2 more answers
A factorial experiment was designed to test for any significant differences in the time needed to perform English to foreign lan
yuradex [85]

Answer:

For main effects

Factor (Language translator) confirms that there is no significance difference between two levels of language translator of main effect at 5% level of significance.

Factor (Types of language) confirms that there is no significance difference between three levels of types of language at 5% level of significance.

also,

For interaction effect between language translator and types of language, there is no significant difference that the interaction between language translator and types of language at 5% level of significance.

Step-by-step explanation:

see attached.

3 0
3 years ago
For a school play, the teacher asked the class to set up chairs in 20 rows with 25 chairs in each row. After setting up all the
Sholpan [36]
They set up 495 chairs.

I hope this helps! :)

7 0
3 years ago
Read 2 more answers
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