A device used in golf to estimate the distance d, in yards, to a hole measures the size s, in inches, that the 7-ft pin appears
2 answers:
This is a proportional problem.
The distance 'd' corresponds to the 9 inches.
The 7-ft pin corresponds to the size 's'.
Convert 7ft to 7/3 yds. This way you have equal ratio of yds to inches.
The distance 'd' corresponds to the 9 inches.
The 7-ft pin corresponds to the size 's'.
Convert 7ft to 7/3 yds. This way you have equal ratio of yds to inches.
Answer:
d = yards
Step-by-step explanation:
This problem can be easily solved using proportionality/ratio between similar geometric figures.
Drawing a triangle from the viewers eye to the pin, up the pin, and back to the viewer's eye; and drawing a 2nd triangle from the viewers eye to the edge of the viewfinder up to the apparent height of the pin (the image) in the viewfinder and back to the viewer's eye gives two similar triangles.
The ratio of the height of the image in the viewfinder to the horizontal length between the viewer's eye and the viewfinder (9in) is equal to the ratio of the pin height (8/3 yards) to the distance d from the viewer to the pin, in yards.
The 7 ft pin is 7/3 yards tall. We need to express the pin height in yards so the units will cancel when we take the ratio with distance 'd'.
finding these ratios we can write:
=
d x s = x 9
d = yards
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Answer:
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Step-by-step explanation:
<u>We first have to do the multiplication of the numbers given:</u>
19 * 2,120,400
=> 40287600
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4, 0 2 8 7 6 0 0
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Answer:
a) 99.84% probability that during a year, you can avoid catastrophe with at least one working drive
b) 99.999744% probability that during a year, you can avoid catastrophe with at least one working drive
Step-by-step explanation:
For each disk drive, there are only two possible outcomes. Either it works, or it does not. The disks are independent. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
4% rate of disk drive failure in a year.
This means that 96% work correctly,
a. If all your computer data is stored on a hard disk drive with a copy stored on a second hard disk drive, what is the probability that during a year, you can avoid catastrophe with at least one working drive?
This is when
We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So
We want . So
In which
99.84% probability that during a year, you can avoid catastrophe with at least one working drive
b. If copies of all your computer data are stored on four independent hard disk drives, what is the probability that during a year, you can avoid catastrophe with at least one working drive?
This is when
We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So
We want . So
In which
99.999744% probability that during a year, you can avoid catastrophe with at least one working drive