Given the function f(x) = x-8/2x-2, find f(2) (No answer choices)

Mathematics

2 answers:

Neko [114]3 years ago

5 0

Answer:

f(2) = (2-8)/(2x2 -2) = -6 / 2 = -3

Step-by-step explanation:

Nina [5.8K]3 years ago

4 0

Answer:

The function is -3.

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Can anyone please help me to find the area of this please

valentinak56 [21]

9514 1404 393

Answer:

√35 +3√7 -6 . . . square units

Step-by-step explanation:

The area can be figured a number of ways. The figure can be divided into parts, and the areas of those parts added.

Or, the area of the enclosing rectangle can be found, and the rectangle at upper right that is not shaded can be subtracted from that. We choose the latter.

The overall width is the sum of the given partial widths:

width = (√7 -2) + (2) = √7

Then the area of the bounding rectangle is ...

A = LW = (√5 +3)(√7) = √35 +3√7

The area of the upper right empty-space is ...

A = LW = (3)(2) = 6

Then The area of the shaded figure is ...

√35 +3√7 -6

5 0

3 years ago

5pts and whoever has the correct answer gets brainliest

USPshnik [31]

Answer:

Step-by-step explanation:

8 0

2 years ago

What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth

EleoNora [17]

Check the picture below.

so... you can pretty much see how long RS and QT are, you can just count the units off the grid.

now, let's find QR's length

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&Q&(~ 8 &,& 8~) 
% (c,d)
&R&(~ 14 &,& 16~)
\end{array}~~ 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
QR=\sqrt{(14-8)^2+(16-8)^2}\implies QR=\sqrt{6^2+8^2}
\\\\\\
QR=\sqrt{36+64}\implies QR=\sqrt{100}\implies QR=10$

and let's also find the length for ST

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&S&(~ 20 &,& 16~) 
% (c,d)
&T&(~ 22 &,& 8~)
\end{array}~ 
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
ST=\sqrt{(22-20)^2+(8-16)^2}\implies ST=\sqrt{2^2+(-8)^2}
\\\\\\
ST=\sqrt{4+64}\implies ST=\sqrt{68}\implies ST=\sqrt{4\cdot 17}
\\\\\\
ST=\sqrt{2^2\cdot 17}\implies ST=2\sqrt{17}$

so, add the lengths of all sides, and that's the perimeter of the trapezoid.