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marysya [2.9K]
3 years ago
7

Convert 0.0345mW to MW​

Physics
1 answer:
Rina8888 [55]3 years ago
6 0

Answer:

3.45e-11MV

that is ur answer

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How long does it take light to travel between earth and the nearest star?
sergejj [24]

Answer:

It takes 8.204 minutes for light to travel from the Sun to Earth

Explanation:

The speed of light is 300000 km/s and the nearest star to the Earth is the Sun which is 149.67 million km. therefore it takes about

147.67×10⁶/300000  = 492.233 seconds for light from the Sun to reach Earth or 8.204 minutes

The other next nearest star is Alpha Centauri which is 4 light years away

5 0
3 years ago
Read 2 more answers
What is the period of a satellite in a geosynchronous orbit?
Dominik [7]
<span>23 hours 56 minutes and 4 seconds</span>
8 0
4 years ago
A square plate of copper with 47.0 cm sides has no net charge and is placed ina region of uniform electric field of 75.0 kN/C di
timurjin [86]

Answer:

(a) Charge density σ=6.6375×10²nC/m²

(b) Total charge Q=1.47×10²nC

Explanation:

Given Data

A=47.0 cm =0.47 m

Electric field E=75.0 kN/C

To find

(a) Charge density σ

(b)Total Charge Q

Solution

For (a) charge density σ

From Gauss Law we know that

Φ=Q/ε₀.......eq(i)

Where

Φ is electric flux

Q is charge

ε₀ is permittivity of space

And from the definition of flux

Φ = EA

The flux is  electric field passing  perpendicularly through the surface

Put the this Φ in equation(i)

EA =Q/ε₀

where Q(charge)=σA

EA=(σA)/ε₀

E=σ/ε₀

σ=ε₀E

=(8.85*10^{-12} )*(75.0*10^{3} )\\=6.6375*10^{-7} C/m^{2}\\=6.63*10^{2}nC/m^{2}

σ=6.6375×10²nC/m²

For (b) total charge Q

Q=σA

Q=(6.6375*10^{2} nC/m^{2} )(0.47m)^{2}\\ Q=1.47**10^{2}nC

6 0
3 years ago
NASA sends an unmanned lander to test conditions on the surface of Mars. What is the magnitude of the gravitational force acting
kozerog [31]

Answer:

The magnitude of the gravitational force acting on the lander on the surface of Mars is 512.46 N.

Explanation:

The Universal law of gravity is define as:

F = G \frac{M.m}{R^{2}}  (1)

Where F is the gravitational force, G is gravitational constant, M is the mass of Mars, m is the mass of the lander and R is the radius of Mars.

Before replacing the values in equation 1 it is necessary to express the radius of mars in terms of meters:

R = 3397 kmx\frac{1000 m}{1 km} ⇒ R = 3397000 m

Finally, equation 1 can be used:

F = (6.67x10^{-11} N.m^{2}/Kg^{2}) \frac{(6.42x10^{23} kg)(138.1 kg)}{(3397000 m)^{2}}

F = 512.46 N

Hence, the magnitude of the gravitational force acting on the lander on the surface of Mars is 512.46 N.

4 0
3 years ago
In order for a space shuttle to leave Earth, it must produce a great amount of thrust. Its rocket boosters create this thrusting
bonufazy [111]

Answer:

Orbit

Explanation:

The term that describes motion of the shuttle around earth is called as<em> Orbit.</em>

The orbit is defined as a regular repeating path that object takes around another.

The shuttle circles around the earth at a constant distance from earth surface is because of earth gravity and forward motion of earth.

5 0
4 years ago
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