Answer:
A) yes
Explanation:
First section of trip: 30 miles in 40 minutes
Second section of trip: 15 miles in 20 minutes
The formula for speed is distance over time 
Calculate the speeds for each section of the trip.
First:
k = d/t
k = 30miles/40minutes <= reduce fraction by 10 (30÷10 and 40÷10)
k = 3 miles / 4 minutes
Second:
k = d/t
k = 15miles/20minutes <= reduce fraction by 5 (15÷5 and 20÷5)
k = 3 miles / 4 minutes
Therefore there is a constant speed because both sections of the trip are driving at "3 miles / 4 minutes".
3 miles / 4 minutes can be also formatted as:
0.75 miles per minute.
It’s doesn’t change meaning it’s 0
Answer:
Add an arrow above the symbol p to show it is a vector. Sometimes it is italicized in textbooks.
Explanation:
Answer:
The angular acceleration is 11.66 rad/s²
Explanation:
Step 1: Given data
Three forces are applied to a solid cylinder of mass 12 kg
F1 = 15 N
F2 = 24 N
F3 = 19 N
R2 = 0.22m
R3 = 0.10m
Step 2: Find the magnitude of the angular acceleration
I = ½mr² = ½ * 12kg * (0.22m)² = 0.29 kg*m²
torque τ = I*α
τ = F2*R2 - F1*R1 = 24N*0.22m - 19N*0.10m = 3.38 N*m
This means
I = ½mr² = 0.29 kg*m²
τ = I*α = 3.38 N*m
OR
0.29 kg*m² * α = 3.38 N*m
α = 11.655 rad/s² ≈11.66 rad/s²
The angular acceleration is 11.66 rad/s²
