NASA sends an unmanned lander to test conditions on the surface of Mars. What is the magnitude of the gravitational force acting
1 answer:
Answer:
The magnitude of the gravitational force acting on the lander on the surface of Mars is 512.46 N.
Explanation:
The Universal law of gravity is define as:
(1)
Where F is the gravitational force, G is gravitational constant, M is the mass of Mars, m is the mass of the lander and R is the radius of Mars.
Before replacing the values in equation 1 it is necessary to express the radius of mars in terms of meters:
R = ⇒ R =
Finally, equation 1 can be used:
Hence, the magnitude of the gravitational force acting on the lander on the surface of Mars is 512.46 N.
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The central force acting on the electron as it revolves in a circular orbit is .
The given parameters;
- <em>speed of electron, v = 2.2 x 10⁶ m/s</em>
- <em>radius of the circle, r = 4.63 x 10⁻¹¹ m</em>
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The central force acting on the electron as it revolves in a circular orbit is calculated as follows;
where;
is mass of electron = 9.11 x 10⁻³¹ kg
Thus, the central force acting on the electron as it revolves in a circular orbit is .
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Answer:
1.43 s
Explanation:
The time it takes for the container to reach the ground is determined only by the vertical motion of the container, which is a free-fall motion, so a uniformly accelerated motion with a constant acceleration of g=9.8 m/s^2 towards the ground.
The vertical distance covered by an object in free fall is given by
where
u = 0 is the initial vertical speed
t is the time
a= g = 9.8 m/s^2 is the acceleration
since u=0, it can be rewritten as
And substituting S=10.0 m, we can solve for t, to find the duration of the fall: