Answer:
<em>The distance the car traveled is 21.45 m</em>
Explanation:
<u>Motion With Constant Acceleration
</u>
It occurs when an object changes its velocity at the same rate thus the acceleration is constant.
The relation between the initial and final speeds is:
![v_f=v_o+at\qquad\qquad [1]](https://tex.z-dn.net/?f=v_f%3Dv_o%2Bat%5Cqquad%5Cqquad%20%5B1%5D)
Where:
a = acceleration
vo = initial speed
vf = final speed
t = time
The distance traveled by the object is given by:
![\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3Dv_o.t%2B%5Cfrac%7Ba.t%5E2%7D%7B2%7D%5Cqquad%5Cqquad%20%5B2%5D)
Solving [1] for a:
![\displaystyle a=\frac{v_f-v_o}{t}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20a%3D%5Cfrac%7Bv_f-v_o%7D%7Bt%7D)
Substituting the given data vo=0, vf=6.6 m/s, t=6.5 s:
![\displaystyle a=\frac{6.6-0}{6.5}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20a%3D%5Cfrac%7B6.6-0%7D%7B6.5%7D)
![a = 1.015\ m/s^2](https://tex.z-dn.net/?f=a%20%3D%201.015%5C%20m%2Fs%5E2)
The distance is now calculated with [2]:
![\displaystyle x=0*6.5+\frac{1.015*6.5^2}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D0%2A6.5%2B%5Cfrac%7B1.015%2A6.5%5E2%7D%7B2%7D)
x = 21.45 m
The distance the car traveled is 21.45 m
Answer:
a) K = 0.63 J, b) h = 0.153 m
Explanation:
a) In this exercise we have a physical pendulum since the rod is a material object, the angular velocity is
w² =
where d is the distance from the pivot point to the center of mass and I is the moment of inertia.
The rod is a homogeneous body so its center of mass is at the geometric center of the rod.
d = L / 2
the moment of inertia of the rod is the moment of a rod supported at one end
I = ⅓ m L²
we substitute
w =
w =
w =
w = 4.427 rad / s
an oscillatory system is described by the expression
θ = θ₀ cos (wt + Φ)
the angular velocity is
w = dθ /dt
w = - θ₀ w sin (wt + Ф)
In this exercise, the kinetic energy is requested in the lowest position, in this position the energy is maximum. For this expression to be maximum, the sine function must be equal to ±1
In the exercise it is indicated that at the lowest point the angular velocity is
w = 4.0 rad / s
the kinetic energy is
K = ½ I w²
K = ½ (⅓ m L²) w²
K = 1/6 m L² w²
K = 1/6 0.42 0.75² 4.0²
K = 0.63 J
b) for this part let's use conservation of energy
starting point. Lowest point
Em₀ = K = ½ I w²
final point. Highest point
Em_f = U = m g h
energy is conserved
Em₀ = Em_f
½ I w² = m g h
½ (⅓ m L²) w² = m g h
h = 1/6 L² w² / g
h = 1/6 0.75² 4.0² / 9.8
h = 0.153 m
This is a "trick" question.
If the elevator is traveling at constant speed, it means it is at rest. This means anything inside the elevator traveling at constant speed, weights the same as in an elevator not moving -also at rest-.
So the 100N weight's weight doesn't change in an elevator traveling at constant speed.
Answer:
Explanation:
Particles of a solid are closely packed, and when a solid is hit to produce a sound the kinetic energy present in the solid will cause the particles to vibrate vigorously in the intermolecular spaces in the solid, whereas the paticles of liquids and gases are rather further apart therefore having large intermolecular spaces between particles.
Answer:
No it can not
Explanation: Kinetic energy is the energy of motion so it can not be negative the kinetic energy can only be at a point of "0" which is when its not moving. (I hope this helped) :))