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3 years ago

5

You are looking at yourself in a plane mirror, a distance of 3 meters from the mirror. Your brain interprets what you are seeing

in the mirror as being a person standing ______ meters from you.
A.12
B. 6
C. 1.5
D 4.5

1 answer:

Maslowich3 years ago

5 0

Answer:6

Explanation:

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Prove the identity <br>Trigonometry grade 10

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Answer:

and is in photo given.I didn't get time to type.

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3 years ago

On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a golf club improvised from a tool. The free-f

aliya0001 [1]

Answer:

15.3 s and 332 m

Explanation:

With the launch of projectiles expressions we can solve this problem, with the acceleration of the moon

gm = 1/6 ge

gm = 1/6 9.8 m/s² = 1.63 m/s²

We calculate the range

R = Vo² sin 2θ / g

R = 25² sin (2 30) / 1.63

R= 332 m

We will calculate the time of flight,

Y = Voy t – ½ g t2

Voy = Vo sin θ

When the ball reaches the end point has the same initial height Y=0

0 = Vo sin  t – ½ g t2

0 = 25 sin (30) t – ½ 1.63 t2

0= 12.5 t – 0.815 t2

We solve the equation

0= t ( 12.5 -0.815 t)

t=0 s

t= 15.3 s

The value of zero corresponds to the departure point and the flight time is 15.3 s

Let's calculate the reach on earth

R2 = 25² sin (2 30) / 9.8

R2 = 55.2 m

R/R2 = 332/55.2

R/R2 = 6

Therefore the ball travels a distance six times greater on the moon than on Earth

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3 years ago

You watch a distant lady driving nails into her front porch at a regular rate of 1 stroke per second. You hear the sound of the

Igoryamba

Answer:

λ = 1360 m

Explanation:

Given data:

frequency of driving nails is given as 1 stroke per second mean at every 0.25 sec she hit the nails

speed of sound is given as 340 m/s

we know that the wave equation is given as

Speed = frequency × wavelength,

v = f × λ

where,

v = speed in meters/second (m/s)

f = frequency in Hertz (Hz)

substituing value to get wavelength of her driving nails

$340 m/s = (1Hz)\times \lambda$

$\lambda = \frac{340}{0.25}$

λ = 1360 m

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3 years ago

Read 2 more answers

The planet Krypton has a mass of 8.8 × 1023 kg and radius of 2.5 × 106 m. What is the acceleration of an object in free fall nea

djverab [1.8K]

Answer:

Acceleration, $a=9.39\ m/s^2$

Explanation:

Given that,

Mass of the planet Krypton, $m=8.8\times 10^{23}\ kg$

Radius of the planet Krypton, $r=2.5\times 10^{6}\ m$

Value of gravitational constant, $G=6.6726\times 10^{-11}\ Nm^2/kg^2$

To find,

The acceleration of an object in free fall near the surface of Krypton.

Solution,

The relation for the acceleration of the object is given by the below formula as :

$a=\dfrac{Gm}{r^2}$

$a=\dfrac{6.6726\times 10^{-11}\times 8.8\times 10^{23}}{(2.5\times 10^{6})^2}$

$a=9.39\ m/s^2$

So, the value of acceleration of an object in free fall near the surface of Krypton is $9.39\ m/s^2$

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3 years ago

A football is kicked at ground level with the speed of 32 m/s at an angle of 40 degrees to the horizontal. how much later does i

LUCKY_DIMON [66]

the question was a football is kicked at ground level with a speed of 32 m/s the an angle of 40 degrees to the horizontal how much later does it hit the ground probably like 30 more or 40 sense it was around 32

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