Answer:
First question:
The graph of has a vertical asymptote at x =
and a horizontal asymptote at y =
Second question:
The graph of equation has a horizontal asymptote at y = -3 ⇒ C
Step-by-step explanation:
The vertical asymptotes will occur at the values of x for which make the denominator is equal to zero
The horizontal asymptotes will occur if:
- Both polynomials are the same degree, divide the coefficients of the highest degree terms
- The polynomial in the numerator is a lower degree than the denominator, the x-axis (y = 0) is the horizontal asymptote
First question:
∵
- To find the vertical asymptote equate the denominator by 0
to find the value of x
∵ The denominator is 2 - 3x
∴ 2 - 3x = 0
- Add 3x to both sides
∴ 2 = 3x
- Divide both sides by 3
∴ = x
∴ The graph has a vertical asymptote at x =
To find the horizontal asymptote look at the highest degree of x in both numerator and denominator
∵ The denominator and the numerator has the same degree of x
- Divide the coefficient of x of the numerator and denominator
∵ The coefficient of x in the numerator is -2
∵ The coefficient of x in the denominator is -3
∵ -2 ÷ -3 =
∴ The graph has a horizontal asymptote at y =
The graph of has a vertical asymptote at x =
and a horizontal asymptote at y =
Second question:
The graph has a horizontal asymptote at y = -3
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<em>means the numerator and the denominator has same highest degree and the coefficient of the highest degree in the numerator divided by the coefficient of the highest degree in the denominator equal to -3</em>
- In all answers the numerator and the denominator have the same highest degree
- Lets look for the coefficients of x up and down to find which one gives quotient of -3
∵ In answer A the quotient is 1 because x up and down have
coefficient 1
∵ In answer B the quotient is because the coefficient of x
up is 1 and down is -3
∵ In answer D the quotient is -1 because the coefficient of x
up is 3 and down is -3
∵ In answer C the quotient is -3 because the coefficient of x up
is -3 and down is 1
∴ The graph of equation has a horizontal asymptote at y = -3