Given:
Consider the line segment YZ with endpoints Y(-3,-6) and Z(7,4).
To find:
The y-coordinate of the midpoint of line segment YZ.
Solution:
Midpoint formula:
![Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)](https://tex.z-dn.net/?f=Midpoint%3D%5Cleft%28%5Cdfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%5Cdfrac%7By_1%2By_2%7D%7B2%7D%5Cright%29)
The endpoints of the line segment YZ are Y(-3,-6) and Z(7,4). So, the midpoint of YZ is:
![Midpoint=\left(\dfrac{-3+7}{2},\dfrac{-6+4}{2}\right)](https://tex.z-dn.net/?f=Midpoint%3D%5Cleft%28%5Cdfrac%7B-3%2B7%7D%7B2%7D%2C%5Cdfrac%7B-6%2B4%7D%7B2%7D%5Cright%29)
![Midpoint=\left(\dfrac{4}{2},\dfrac{-2}{2}\right)](https://tex.z-dn.net/?f=Midpoint%3D%5Cleft%28%5Cdfrac%7B4%7D%7B2%7D%2C%5Cdfrac%7B-2%7D%7B2%7D%5Cright%29)
![Midpoint=\left(2,-1\right)](https://tex.z-dn.net/?f=Midpoint%3D%5Cleft%282%2C-1%5Cright%29)
Therefore, the y-coordinate of the midpoint of line segment YZ is -1.
Answer:
slope is y=3x-16 if thats what you are trying to find out
Step-by-step explanation:
Total paint is 5oz + 9oz = 14oz
Blue paint is 9/14 = 64.3%
For this case we have the following expression:
![\frac{1}{3} + \frac{1}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%7D%20%2B%20%5Cfrac%7B1%7D%7B3%7D%20)
We observe that the numerator in both fractions is smaller than the denominator.
Therefore, we are in the presence of two proper fractions.
Since the denominator of both fractions is equal, then the result is given by:
![\frac{1}{3} + \frac{1}{3} = \frac{2}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%7D%20%2B%20%5Cfrac%7B1%7D%7B3%7D%20%3D%20%5Cfrac%7B2%7D%7B3%7D%20)
The numerators are added and the denominator is the same.
The result is also a proper fraction because the numerator is smaller than the denominator.
Answer:
h(x) = x/2 - 1/2
Step-by-step explanation:
Here's the procedure for finding the inverse function algebraically:
1. Replace the label 'f(x)' with the label 'y:' y = 2x + 1
2. Interchange x and y: x = 2y + 1
3. Solve the resulting equation for y: 2y = x - 1, or y = (1/2)(x - 1) or y = x/2 - 1/2
This result corresponds to the 1st given possible answer choice.
The desired inverse function is h(x) = x/2 - 1/2