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3 years ago

Find the slope and y-intercept of y – 3x = 2

Mathematics

2 answers:

suter [353]3 years ago

8 0

Answer:

slope is 3/1 y=2

Step-by-step explanation:

OverLord2011 [107]3 years ago

5 0

Slope: 3
Y-intercept: 2

Slope-intercept form can be represented as y=mx+b. The m is the slope and the b is the y-intercept. To get the equation into y=mx+b, add 3x to both sides to get the y by itself. When you add 3x to both sides you will get y=3x+2. The slope will be 3 because the 3 is in place of the m. The y-intercept is 2 because the 2 is in the place of the b.

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10 snails is to be chosen from this population. Find the probability that the percentage of streaked-shelled snails in the sampl

Alex17521 [72]

Here is the full question:

$The \ shell \ of \ the \ land \ snail \ Limocolaria \ martensiana \ has \ two \ possible \ color$ $forms: \ streaked \ and \ pallid. \ In \ a \ certain \ population \ of \ these \ snails, \ 60\% \ o f \ the$ $individuals \ have \ streaked \ s hells.\ 16 \ Suppose \ that \ a \ random \ sample \ of \ 10 \ snails$ $is \ to \ be \ chosen \ from \ this \ population. \ F ind \ the \ probabilit y \ that \ the \ percentage \ of$

$streaked-shelled \ snails \ in \ t he \ sample \ will \ be$

$(a) 50\%. \ (b) 60\%. \ (c) 70\%.$

Answer:

(a) 0.2007

(b) 0.2510

Step-by-step explanation:

Given that:

The sample size = 10

Sample proportion= 60% 0.6

Let X represents the no of streaked-shell snails.

$X \sim Binom (n =1 0, p = 0.60)$

The Probability mass function (X) is:

$P(X =x)= (^n_x) p^x(1-p)^{n-x}; x = 0,1,2,3...$

The Binomial probability with mean μ = np

= 10 * 0.6

= 6

Standard deviation σ = $\sqrt{np(1-p)}$

= $\sqrt{10*0.6*(1-0.6)}$

= 1.55

The probability that the percentage of the streaked-shelled snails in the sample will be:

$P(X = 0.5) = ^nC_x p^x (1 -p) ^{(n-x)}$

$= ^{10}^C_5 * (0.6)^5(1-0.6)^{10-5}$

$= \dfrac{10!}{5!(10-5)!} * (0.6)^5(1-0.6)^{10-5}$

= 0.2007

$P(X = 0.6) = ^nC_x p^x (1 -p) ^{(n-x)}$

$= ^{10}^C_6 * (0.6)^6(1-0.6)^{10-6}$

$= \dfrac{10!}{6!(10-6)!} * (0.6)^6(1-0.6)^{10-6}$

= 0.2510

$P(X = 0.7) = ^nC_x p^x (1 -p) ^{(n-x)}$

$= ^{10}^C_7 * (0.6)^7(1-0.6)^{10-7}$

$= \dfrac{10!}{7!(10-7)!} * (0.6)^7(1-0.6)^{10-7}$

= 0.2150

7 0

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Snowcat [4.5K]

Answer:

Step-by-step explanation:

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xxTIMURxx [149]

247 is 10 more than 237

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velikii [3]

Answer:

129

Step-by-step explanation:

144x0.90=129

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3 years ago

A highway runs east-west between two towns C and B that are 25 km apart. Town A lies 15 km directly north from C. A straight roa

arsen [322]

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