X^2+y^2-10x-16y+53=0 What is the center of the circle? What is the radius of the circle?

Mathematics

1 answer:

Anon25 [30]2 years ago

7 0

Answer:

Step-by-step explanation:

hello : Completing The Square

X²+y²-10x-16y+53=0 means : (x²-10x+25-25)+(y²-16y+16-16)+53 =0

(x²-10x+25)-25)+(y²-16y+64)-64+53 =0

(x+5)²+(y-8)² -25-64+53=0

(x+5)²+(y-4)² = 6² standard form

the center is (-5 , 4) and the radius : 6

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