Answer:
<h2>L=203 yards</h2><h2>W=52 yards</h2>
Step-by-step explanation:
Step one:
given data
perimeter= 510 yards
let the width be x, width=x
length= (4x-5)-----quadruple mean 4 times
Step two:
the expression for perimeter is
P=2L+2W
510=2(4x-5)+2x
510=8x-10+2x
510+10=8x+2x
520=10x
divide both sides by 10
x=520/10
x=52
the width is 52 yards
the lenght is (4x-5)
L=4(52)-5
L=208-5
L=203 yards
Answer:
For D. X= 3, or 0 but probably not 0
For the 2nd picture you sent, x= -2, or -3
Step-by-step explanation:
So for D. you want to make sure you only have 1 Variable, and since we know y=x squared + 7x+5, we subsitute y for what it is equal to.
Then we refine the question, which takes it out to
x squared-3x+5=5 (because the 7x-10x = 3x)
We subtract 5 from both sides which leaves us with x Squared - 3x= 0
Which we then solve with the Quadratic formula. and we separate the solutions to get the different answers for 3, and 0
50,779/590 is 90.7125 but rounded to 90.71
Answer:
a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle
Step-by-step explanation:
Let l = the original length of the original rectangle
Let w = the original width of the original rectangle
From the description of the problem, we can construct the following two equations
l=2*w (Equation #1)
(l+4)*(w+4)=l*w+88 (Equation #2)
Substitute equation #1 into equation #2
(2w+4)*(w+4)=(2w*w)+88
2w^2+4w+8w+16=2w^2+88
collect like terms on the same side of the equation
2w^2+2w^2 +12w+16-88=0
4w^2+12w-72=0
Since 4 is afactor of each term, divide both sides of the equation by 4
w^2+3w-18=0
The quadratic equation can be factored into (w+6)*(w-3)=0
Therefore w=-6 or w=3
w=-6 can be rejected because the length of a rectangle can't be negative so
w=3 and from equation #1 l=2*w=2*3=6
I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.
Answer:
A. 26.10 cm
B. 118.95 cm
Step-by-step explanation:
ST = 41^2 - 40^2 = c^2 = hypotenuse
ST = 1681 - 1600 = c^2
ST = c^2 = sq rt 681 =26.0959767014 = 26.1cm
Nearest 100th = 26.10
Length = 26.10 cm to nearest 100th
Perimeter of RSU we find (M) of SU first then add that to the other 3 lengths on the exterior of the triangle.
SU = 10^2 + 26.1^2 = c^2 = hypotenuse
SU = 100 + 681.21 = c^2
SU = c^2 = sqrt 781.21 = 27.9501341678 = 27.95cm
P TOTAL RSU = SU + TR + RS + TU
= 27.95 + 40+ 41 + 10 = 118.95cm
