Ask question

Ask question

All categories

3 years ago

12

Una avenida está siendo asfaltada por etapas. En la primera etapa se asfaltó la mitad; en la segunda, la quinta parte, y en la t

ercera, la cuarta parte del total. ¿Cuál es la longitud de la avenida si aún faltan 200 m por asfaltar?

1 answer:

s344n2d4d5 [400]3 years ago

7 0

Answer:

Sabemos que:

L es el largo de la avenida.

En la primer etapa se asfalto la mitad, L/2, entonces lo que queda por asfaltar es:

L - L/2 = L/2.

En la segunda etapa se asfalto la quinta parte, L/5, entonces lo que queda por asfaltar es:

L/2 - L/5 = 5*L/10 - 2*L/10 = (3/10)*L

En la tercer etapa se asfalto la cuarta parte del total, L/4, entonces lo que queda por asfaltar es:

(3/10)*L - L/4 = 12*L/40 - 10L/40 = (2/40)*L

Y sabemos que este ultimo pedazo que queda por asfaltar es de 200m:

(2/40)*L = 200m

L = 200m*(40/2) = 4,000m

You might be interested in

What is 9/10 + 7/15

Yakvenalex [24]

$\huge\text{Hey there!}$

$\mathsf{\dfrac{9}{10}+\dfrac{7}{15}}$

$\large\textsf{FIRST: FIND the LCD (Lowest Common Denominator) then solve}\\\large\textsf{from there!}$

$\large\textsf{If you have calculated it correctly, you should have came up with \underline{\bf 30}}\\\large\textsf{as your LCD (Lowest Common Denominator).}$

$\mathsf{= \dfrac{9\times3}{10\times3}+ \dfrac{7\times2}{15\times2}}$

$\mathsf{9\times3=\bf 27}\\\mathsf{10\times3=\bf 30}\\\\\mathsf{7\times2=\bf 14}\\\mathsf{15\times2=\bf 30}$

$\mathsf{= \dfrac{27}{30}+\dfrac{14}{30}}$

$\mathsf{= \dfrac{27+14}{30}}$

$\mathsf{27+ 14=\bf 41}\\\\\mathsf{30+0=\bf 30}$

$\mathsf{= \dfrac{41}{30}}\large\textsf{ which you could convert to }\mathsf{1 \dfrac{11}{30}}$

$\boxed{\boxed{\large\textsf{ANSWER: }\bf \dfrac{41}{30} \large\textsf{ or }\mathsf{\bf 1 \dfrac{11}{30}\large\textsf{ because they both equal the same thing}}}}}\huge\checkmark$

$\large\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

6 0

2 years ago

Read 2 more answers

An experiment observing the growth of two germ strand populations finds these patterns.

Mice21 [21]

Answer:

$R(x) = (1.3)^{3x-8}$

Step-by-step explanation:

Given

$A(x) = (1.3)^{x + 9}$

$B(x) = (1.3)^{4x + 1}$

Required

Ratio B(x) to A(x)

This is calculated as:

$R(x) = B(x) : A(x)$

Express as fraction

$R(x) = \frac{B(x) }{A(x)}$

Substitute: $A(x) = (1.3)^{x + 9}$ and $B(x) = (1.3)^{4x + 1}$

$R(x) = \frac{(1.3)^{4x+1}}{(1.3)^{x+9}}$

Apply law of indices

$R(x) = (1.3)^{4x-x+1-9}$

$R(x) = (1.3)^{3x-8}$

6 0

2 years ago

How do you solve a perfect square trinomial??

Nuetrik [128]

Answer:

Step-by-step explanation:

Here's an example:

x^2 + 6x + 9 = 0

First factorise it:

(x + 3)(x + 3) = 0

So the solution is x = -3 (multiplicity 2)

That is there are 2 roots both -3.

7 0

2 years ago

Using properties of parallel lines

irina1246 [14]

Okay what’s your question

5 0

2 years ago

What is f(6)?<br> f(x) = 5x - 2

valina [46]

Answer:

f(6) = 28

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Algebra I</u>

Functions
Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 5x - 2

f(6) is x = 6

<u>Step 2: Evaluate</u>

Substitute in <em>x</em> [Function]: f(6) = 5(6) - 2
Multiplication: f(6) = 30 - 2
Subtraction: f(6) = 28

5 0

2 years ago

Read 2 more answers