Answer:
It is 14.45 percent
Step-by-step explanation:
The first day is independent from the day before. Therefore the first day probability (of rain) is 20 percent.
The second day (depends on the previous day) rainfall probability is 85 percent.
Finally, the third day (it must be rainy to satisfy the total probability) rainfall probability is 85 percent.
The probability of having three consecutive days which are rainy:
P(all rainy)
=
0.20
×
0.85
×
0.85
=
0.1445
or 14.45 percent.
Answer:
-768a
Step-by-step explanation:
6*-2a = -12a
-12a*64 = -768a
Answer:
Let x equal the recurring decimal:
Create another number with recurring 216s by multiplying the above expression by 1000:
Subtract Equation 1 from Equation 2 to eliminate the recurring digits after the decimal:
Divide both sides by 999:
Simplify:
Answer:
x = 8.8
Step-by-step explanation:
take 20 degree as reference angle .the,
hypotenuse = OQ = x (hypotenuse is always opposite of 90 degree)
perpendicular(opposite) = PQ 3 (opposite of reference angle is perpendicular or also called as opposite)
base(adjacent) = OP (side which lies on the same line where 90 degree and reference angle)
using sin rule
sin 20 = opposite / hypotenuse
0.34 = 3 / x
x = 3/0.34
x = 8.82
x = 8.8
Answer:
The probability that no one in a family of five will be hospitalized in a year is 0,2373
Step-by-step explanation:
Let p denote the probability of being hospitalized during a year,
Then p=0.25
And p' the probability of not being hospitalized during a year is 1-p
Thus p' = 1-p = 1-0.25 = 0.75
The probability that no one in a family of five will be hospitalized in a year is equal to 
. That is
= 
≈ 0,2373
