Answer: Exact form: n = 25/6. Decimal form: n = 4.16. The 6 is repeated. Mixed number form: n = 4 1/6.
Step-by-step explanation: Isolate the variable by <u>dividing</u> each side by factors that doesn't contain the variable.
<em>Hope this helps!</em>
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Answer:
A. x²+x-11
Step-by-step explanation:
Take one of the x values and try them out on all formulas to see if the expected output occurs.
Already with x=2 you get
-5, 28, -3, 27 so you know that only the first formula works.
So, let's begin...
First off, you must note that the question is asking for the d value when you substitute the value of c(x).
You are given the following information:
1. The c(x) value is already given to be 0.75x.
2. The equation to find d of (any value) is 0.8y-5.
So, substitute the value of 0.75x as a y value into 0.8y - 5. This is because you are substituting the value of c(x) for d. This is equal to 0.8 times 0.75x - 5. This is equal to 0.6x - 5, which is the function. Thus, your final answer is d(c(x)) = 0.6x - 5.
If you have any questions please comment. Otherwise, hope this helps! :)
The ratio of heights = ratio of the square roots of the areas because area is 2 dimensional and height is one dimensional.
so required ratio is sqrt 40pi : = sqrt40:sqrt80 = sqrt1: sqrt2 = sqrt (1/2) = 0.7071 to 4 significant figures
♥It says that he adds 12$ each week, and by the end of 3 weeks he had 60. Well if you do 12*3
And that =36.
But as you can see its not 60 so we have to find out how much money he had in there before.
He had 24$ in there before he started doing this.
You can find this by doing 36+x=60 and 36+24=60.
Now if you do 12*15
You get 180.
Now add the 24 dollars he already had in there.
180+24=204
He had 204$ at the end of wk.15
♥Hope this helps!♥
