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schepotkina [342]
4 years ago
10

What value of n is needed to make the statement true?

Mathematics
1 answer:
erma4kov [3.2K]4 years ago
8 0

Answer:

4

Step-by-step explanation:

4 is needed because i said so and you should trust me lol

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wo balls are chosen randomly from an um containing 8 white, 4 black,and 2 orange balls. Suppose that we win $2 for each black ba
umka21 [38]

Answer:

The probability distribution is shown below.

Step-by-step explanation:

The urn consists of 8 white (<em>W</em>), 4 black (<em>B</em>) and 2 orange (<em>O</em>) balls.

The winning and losing criteria are:

  • Win $2 for each black ball selected.
  • Lose $1 for each white ball selected.

There are 8 + 4 + 2 = 14 balls in the urn.

The number of ways to select two balls is, {14\choose 2}=91 ways.

The distribution of amount won or lost is as follows:

Outcomes: WW  WO  WB  BB  BO  OO

X:                 -2      -1      1      4     2      0

Compute the probability of selecting 2 white balls as follows:

The number of ways to select 2 white balls is, {8\choose 2}=28 ways.

The probability of WW is,

P(WW)=\frac{n(WW)}{N}=\frac{28}{91}=0.3077

Compute the probability of selecting 1 white ball and 1 orange ball as follows:

The number of ways to select 1 white ball and 1 orange ball is, {8\choose 1}\times {2\choose 1}=16 ways.

The probability of WO is,

P(WO)=\frac{n(WO)}{N}=\frac{16}{91}=0.1758

Compute the probability of selecting 1 white ball and 1 black ball as follows:

The number of ways to select 1 white ball and 1 black ball is, {8\choose 1}\times {4\choose 1}=32 ways.

The probability of WB is,

P(WB)=\frac{n(WB)}{N}=\frac{32}{91}=0.3516

Compute the probability of selecting 2 black balls as follows:

The number of ways to select 2 black balls is, {4\choose 2}=6 ways.

The probability of BB is,

P(BB)=\frac{n(BB)}{N}=\frac{6}{91}=0.0659

Compute the probability of selecting 1 black ball and 1 orange ball as follows:

The number of ways to select 1 black ball and 1 orange ball is, {4\choose 1}\times {2\choose 1}=8 ways.

The probability of BO is,

P(BO)=\frac{n(BO)}{N}=\frac{8}{91}=0.0879

Compute the probability of selecting 2 orange balls as follows:

The number of ways to select 2 orange balls is, {2\choose 2}=1 ways.

The probability of OO is,

P(OO)=\frac{n(OO)}{N}=\frac{1}{91}=0.0110

The probability distribution of <em>X</em> is:

Outcomes:    WW     WO        WB         BB        BO         OO

X:                    -2          -1            1            4            2            0

P (X):           0.3077  0.1758  0.3516  0.0659  0.0879  0.0110

3 0
4 years ago
Jason is covering an ottoman with fabric. The ottoman is in the shape of a rectangular prism that is 37 cm long, 21 wide, and 30
GrogVix [38]

Answer:

4,257 m²

Step-by-step explanation:

step 1

Find the lateral area of the rectangular prism (ottoman)

The lateral area is

LA=PH

where

P is the perimeter of the base

H is the height of the prism

Find the perimeter of the base P

P=2(37+21)=116 cm

we have H=30 cm

<em>Find the lateral area</em>

LA=116(30)=3,480 m²

step 2

Find the area of the top of the ottoman

B=37*21=777 m²

step 3

we know that

The fabric needed to cover the sides and top of the ottoman is equal to sum the lateral area plus the area of the top

3,480+777=4,257 m²

7 0
3 years ago
Which step can be used to prove that triangle EFG is also a right triangle?
BARSIC [14]
"Prove that triangles are congruent by SSS property and hence angle EGF is equal to angle KML" is the step among the choices given that <span>can be used to prove that triangle EFG is also a right triangle. The correct option among all the options that are given in the question is the third option. I hope it helps you.</span>
7 0
3 years ago
Read 2 more answers
Is the relation a fun? Why
djverab [1.8K]

Answer:

the answer is yellow one

4 0
3 years ago
Select the correct answer.
kap26 [50]

Answer:

The answer to your question is the letter C

Step-by-step explanation:

To answer this question just look at the graph, the solution to the system of the quadratic equation and the linear function, are the points where these function cross.

The first point where these functions cross is Point C

The second point where these functions cross is Point E

5 0
3 years ago
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