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Illusion [34]
3 years ago
9

{[8-3)×2]+[(5×6)-5]}÷5​

Mathematics
1 answer:
tatyana61 [14]3 years ago
6 0

Answer:

35

Step-by-step explanation:

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9 A rectangle of perimeter 42 cm is
lianna [129]

Answer:

The correct answer is = p = 15 and q = 6.

Step-by-step explanation:

Given:

Perimeter of rectangle = 42 cm

p - q = 9 cm

length = p

width = q

we know:

Perimeter of rectangle= 2(l+w)

solution:

42 = 2(P+q)

21= p+q

Difference of p and q = 9 cm.

Then, P+q=21 .... 1

P-q=9 ....2

Adding both 1 and 2

2P = 30

P= 15cm and

q = 15-9

= 6cm

5 0
3 years ago
In 2008 election there was 28 blue states and 22 red states express the red and blue states as fractions in lowest terms of the
Basile [38]
Let's start with the blue states. Out of 50 states, 28 of them were blue.
Therefore, the fraction would be 28/50. Let's reduce it.
28/50=14/25 --> these are the lowest terms for this fraction
Use a calculator to find the decimal solution --> 14/25= .56

Now, let's do the red states. Out of the 50 states, 22 of them were blue.
22/50=11/25 --> lowest terms
Use a calculator --> 11/25= .43
8 0
3 years ago
Question : <br> 3x-9y+12=?
PSYCHO15rus [73]
Simplifyiing 
the greatest common factor is 3  so 

3x - 9y + 12 = 3(x - 3y + 4)
5 0
3 years ago
Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.
Sindrei [870]

Answer:

a) P(X=3) = 0.1

b) P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

c) P(X=4) = 0.3

d) P(X=0) = 0.2

e) E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

f) E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

Step-by-step explanation:

We have the following distribution

x      0     1     2   3   4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

P(X=3) = 0.1

Part b

We want this probability:

P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

Part c

For this case we want this probability:

P(X=4) = 0.3

Part d

P(X=0) = 0.2

Part e

We can find the mean with this formula:

E(X)= \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

Part f

We can find the second moment with this formula

E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

4 0
3 years ago
Complete the table... plz help ​
ICE Princess25 [194]

Answer:

3=20

4=15

5=12

Step-by-step explanation:

4 0
3 years ago
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