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Burka [1]
3 years ago
8

Need help asap !!!! It also said round to the nearest tenth

Mathematics
1 answer:
Over [174]3 years ago
4 0

Answer:

4524.9

Step-by-step explanation:

<u>Area of a parallelogram:</u>

A = bh

A = 63 x 90

A = 5670

<u>Area of half-circle:</u>

A = (πr²)/2

A = (π x 27²)/2

A = (π x 729)/2

A = 729/2π

<u>Combined:</u>

5670 - 729/2π

4524.9

You might be interested in
Attachment is shown in the bottom
Leokris [45]

Answer: She is correct because each ratio is equivalent to 5:1, except for the last one, which is 1:5

5/1 = 5:1

10/2 = 5:1

25/5 = 5:1

10/50 = 1:5

5 0
3 years ago
Show the original equation, then solve for x
Lina20 [59]

Answer: 24.7

cos 54° = x/42

⇔ x = 42. cos 54°

⇔ x ≈ 24.7

Step-by-step explanation:

6 0
3 years ago
One line segment is 5 emmore than 4 times the
ollegr [7]
Let the length of the 1st line segment = x

then the length of the second line segment = 4x + 5

The difference in their lengths = 35

so 4x + 5 - x = 35 ... [longer - shorter = 35]

3x = 30

x = 10

so the shorter (1st) line segment is 10 cm long

and the longer (2nd) line segment is 4 * 10 + 5 = 45 cm long
7 0
3 years ago
A high school has 40 players on the football team. The summary of the players' weights is given in the box plot. Approximately,
yulyashka [42]

Answer:

About 91%

Step-by-step explanation:

According to the box plot provided :

Total number of students = 40

Minimum weight = 152 pounds

Third quartile (Q3) = 245

The approximate percentage of students that weigh 245 kg or less

About 10 of the intervals out of the 11 coverage interval of the box plot fall between 152 and 254 ; Hence,

(10 / 11) * 100

90.90

= about 91 % of the total students weigh 245 kg or less

4 0
3 years ago
What are the holes, VA, domain, HA, and Range of n+8/6n? Please help!!
-BARSIC- [3]

Answer:

We show that f(x) n+8/6n = 6 x n = 0

which flips the n+8/1 = 0+8/0-6= x = 3  this is the range.

For the HA we would work left to right.

x goes to positive or negative infinity and is determined by the highest degree terms of the polynomials in the numerator and the denominator. This particular function has polynomials of degree 0 in both the numerator and the denominator

If say n+8 was n+2 then we would use the 2/-2+3 and get 1 and show the hole as the source;

hole : -2+1 as non equal sign. but not in the case of n+8/6n

-2+1 represents 1/3 symmetry.

We see for n+8/6n  with interpreted back into the zero format minus

-0+8/-0-6 we see there is symmetry and can work on the left side of graph and flip over. Where 0 = n+8 and 1=nx6

Step-by-step explanation:

There would be no way of doing the others unless the exponents had been squared ^2

If they were squared then the domain will be (-infinity -3) parenthesis

union of( -3 -2) union of +2 to negative infinity.

There is not a vertical asymptote as the numerator divides into dominator at point 8 as a decimal.

The holes are then closed.

7 0
3 years ago
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