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Burka [1]
3 years ago
8

Need help asap !!!! It also said round to the nearest tenth

Mathematics
1 answer:
Over [174]3 years ago
4 0

Answer:

4524.9

Step-by-step explanation:

<u>Area of a parallelogram:</u>

A = bh

A = 63 x 90

A = 5670

<u>Area of half-circle:</u>

A = (πr²)/2

A = (π x 27²)/2

A = (π x 729)/2

A = 729/2π

<u>Combined:</u>

5670 - 729/2π

4524.9

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Answer:

64

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
6) find HJ<br> 8)find IK
Anastasy [175]

Answer:

HJ = 17

IK = 30

Step-by-step explanation:

to find HI :

GH : 2

HI : ?

IJ : 12

GI : 7

HI = GI - GH

HI = 7- 2

HI = 5

HI + IJ = HJ

5 + 12 = HJ

17 = HJ

To find IK

IJ = ?

JK = 12

KL = ?

IL = 49

JL = 31

To find IK we need to find KL and IJ

KL = JL - JK

KL = 31 - 12

KL = 19

IJ = IL - (JK + KL)

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IJ = 18

IK = IJ + JK

IK = 18 + 12

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4 0
3 years ago
The diagonals of a quadrilateral QRST intersect at P(-1,3). QRST has vertices at Q(3,6) and R(-4,5). What must be the coordinate
erica [24]

S = (-5,0)

T = (2,1)

Step-by-step explanation:

Step 1 :

Given

Q = (3,6) and R = (-4,5). P = (-1,3)

Let S be (a,b) and T be (c,d)

The diagonals of a parallelogram bisect each other. so in order to ensure that QRST is a parallelogram, P must be the mid point of the diagonals QS and RT.

Step 2 :

P is the midpoint  of QS

So we have (3+a) ÷ 2 =  -1  and (6 + b) ÷ 2 = 3

=> 3 + a = -2    and 6 + b = 6

=> a = -5  and b =0

So S should be (-5,0)

Step 3 :

P is the midpoint  of RT

So we have (-4+c) ÷ 2 =  -1  and (5 + d) ÷ 2 = 3

=> -4+ c = -2    and 5 + d = 6

=> c = 2  and d =1

So T should be (2,1)

Step 4 :

Answer :

S = (-5,0)

T = (2,1)

6 0
3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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