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3 years ago

A bowl shaped like a sphere has a radius of 15 cm. Which is closest to the amount of air needed to fill the ball?

2 answers:

6 0

The formula for a sphere is 4/3*pi*r^3 so we replace 15 with 5 since 15 is the radius and after multiplying everything you get 14,137.17 which can be rounded the 14,130 which is B

SIZIF [17.4K]3 years ago

4 0

I believe it is D not quite sure

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128.34 as a mixed number in simplest form

katrin2010 [14]

128.34
= 128+ 0.34
= 128+ 34/100
= 128+ (34/2) / (100/2)
= 128+ 17/50
= 128 17/50

128.34 written as a mixed number is 128 17/50~

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2 years ago

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3 years ago

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6. Find the values for each of the following: a. 3 times 5 in Z1o b. 3 times 5 in Zs c. 3 times 5 in Z3 e. 5 3 in Z1o

Anettt [7]

Answer: The calculations are done below.

Step-by-step explanation: We are given to find the values for each of the following :

(A) 3 times 5 in $\mathbb{Z}_{10}.$

We know that

$\mathbb{Z}_{10}=\{0,1,2,3,4,5,6,7,8,9\}(\textup{mod}10).$

Therefore, we get

$3\times5=15(\textup{mod}10)=5.$

(B) 3 times 5 in $\mathbb{Z}_{5}.$

We know that

$\mathbb{Z}_{5}=\{0,1,2,3,4\}(\textup{mod}5).$

Therefore, we get

$3\times5=15(\textup{mod}5)=0.$

(C) 3 times 5 in $\mathbb{Z}_{3}.$

We know that

$\mathbb{Z}_{3}=\{0,1,2\}(\textup{mod}3).$

Therefore, we get

$3\times5=15(\textup{mod}3)=0.$

(D) 5 times 3 in $\mathbb{Z}_{10}.$

We know that

$\mathbb{Z}_{10}=\{0,1,2,3,4,5,6,7,8,9\}(\textup{mod}10).$

Therefore, we get

$5\times3=15(\textup{mod}10)=5.$

Thus, the required values are evaluated.

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3 years ago