$\bf \stackrel{\textit{area of triangles on the left}}{2\left[\cfrac{1}{2}(2)(3) \right]}+\stackrel{\textit{area of triangles on the right}}{2\left[\cfrac{1}{2}(4)(3) \right]}\implies 6+12\implies 18$

8 0

4 years ago

Y=3/2x+2 <br> 5x-y=5<br> At what point do they meet?

RSB [31]

(2,5) ...........................................................................................

7 0

3 years ago

This is really improtant

Oduvanchick [21]

To determine the lines that are parallel, you will need to find the missing angle length in the pairs of supplementary angles (totaling 180 degree).

180 - 114 = 66 degrees
180 - 112 = 68 degrees

Using these you can see the lines that are parallel. They have matching angle measurements.

c // f
d // e

4 0

3 years ago

Find the unknown angle measure by solving for the given variable

tiny-mole [99]

A straight line is 180°. So you can do:

(15x - 4) + (5x - 8) = 180 Simplify

20x - 12 = 180

20x = 192 Find the value of x

x = 9.6

m∠ABD = 15x - 4 Plug in x = 9.6

m∠ABD = 15(9.6) - 4 = 144 - 4 = 140°

m∠DBC = 5x - 8 Plug in 9.6

m∠DBC = 5(9.6) - 8 = 48 - 8 = 40°

3 0

3 years ago