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cupoosta [38]
3 years ago
10

What is the radius in centimeters of a circle that has a circumference of 16 centimeters

Mathematics
1 answer:
Whitepunk [10]3 years ago
3 0
If I did this correctly all you hade to do is work in reverse. 
1.) Divide 16 by pi (3.14) To get the diameter.16/ 3.14 =5.095541401 or 5.1
2.) Since Diameter is just the radius doubled divide 5.1 by 2. 5.1 /2 = 2.55
3.) Plug it in, use the 2pir equation to see if it works.  2X3.14X2.55= 16.014 or 16.
                     I hope this helps, let me know if you need further explanation.
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Help please ASAP!!!!!!
kobusy [5.1K]

Answer:

y=( )-2     y=2

Step-by-step explanation:

y=mx+b

6 0
3 years ago
Read 2 more answers
A type of elevator has a maximum weight capacity Y1 , which is normally distributed with mean 5000 pounds and standard deviation
alukav5142 [94]

Answer:

 then value is 0.0228

Step-by-step explanation:

Maximum weight capacity= Y1

Elevator's loaf = Y2

probability that is overloaded :

P(Y2 > Y1)

TakingP( Y2 - Y1) > 0

E[Y1 - Y2 ] = 500 - 4000 = 1000

P( Y2 > Y1) = P( Y2 - Y1 > 0 ) = P( Y1 - Y2 < 0 ) ;

E[Y1 - Y2] = 500-4000 = 1000

P (Y2 > Y1 )

then

P (Y1 - Y2 < 0)

P((Y1-Y2)-1000)/50 = (0-1000/500)

P((Y1 - Y2 )  - 2)

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5 0
3 years ago
The window of a burning building is 24 meters above the ground. the base of a ladder is placed 10 meters from the building. How
Orlov [11]
14 meters? Bc 24-10 = 14
3 0
3 years ago
Solve:<br> 2y + 5x=30<br> y = 3x + 4
mafiozo [28]
Replace the second equation y=3x+4 into the first one:
2(3x+4)+5x=30
Now solve for x:
6x+8+5x=30
11x=30-8
11x=22
x=22/11
x=2
Finally, replace x=2 into y=3x+4
y=3*2+4
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So the anwer is x=2, y=10
6 0
3 years ago
Find S5 for a geometric series for which a1=81 and r=1/9.
Minchanka [31]

ANSWER

S_5=91\frac{10}{81}




EXPLANATION


The sum of the first n terms of a geometric sequence is given by;


S_n=\frac{a_1(1-r^n)}{1-r} ,-1


Where n, is the number of terms and a_1 is the first term.


When n=5, we have a_1=81, we get;


S_5=\frac{81(1-(\frac{1}{9})^5)}{1-\frac{1}{9}}


S_5=\frac{81(1-\frac{1}{59049})}{1-\frac{1}{9}}


S_5=\frac{81(\frac{59048}{59049})}{\frac{8}{9}}




S_5=\frac{7381}{81}


S_5=91\frac{10}{81}




6 0
3 years ago
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