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Archy [21]
3 years ago
10

A city garden club is planting a square garden. They drive pegs into the ground at each corner and tie strings between each pair

. The pegs are spaced so that WX ≅ XY ≅ YZ ≅ ZW . How can the garden club use the diagonal strings to verify that the garden is a square? Complete the explanation.
e23

Because both pairs of opposite sides of the quadrilateral garden are congruent, the garden is a parallelogram. The garden is a
(select)
, because all four sides are congruent. If it can be proven that it is also a
(select)
, then the garden is a square. So, if the diagonals
(select)
, then the garden is a square. The club members can measure the lengths of the diagonals.
Mathematics
1 answer:
Dafna1 [17]3 years ago
5 0

Answer:

first blank is "rhombus"

second blank is "rectangle"

third blank is "are congruent"

Step-by-step explanation:

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8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

<em><u>Solution:</u></em>

Given that,

y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4  ----- eqn 2

<em><u>We have to substitute eqn 1 in eqn 2</u></em>

x + 3 = x^2 + 2x - 4

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\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}

x = \frac{-1 \pm \sqrt{ 1 + 28}}{2}\\\\x = \frac{ -1 \pm \sqrt{29}}{2}

x = \frac{ -1 \pm 5.385 }{2}\\\\We\ have\ two\ solutions\\\\x = \frac{ -1 + 5.385 }{2}\\\\x = 2.1925

Also\\\\x = \frac{ -1 - 5.385 }{2}\\\\x = -3.1925

Substitute x = 2.1925 in eqn 1

y = 2.1925 + 3

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Substitute x = -3.1925 in eqn 1

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Answer:

B. Florence promoted economic and social freedom

Step-by-step explanation:

Edgenuity 2020

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---------------------------

Total expectation =   $ .25

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