1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Archy [21]
3 years ago
10

A city garden club is planting a square garden. They drive pegs into the ground at each corner and tie strings between each pair

. The pegs are spaced so that WX ≅ XY ≅ YZ ≅ ZW . How can the garden club use the diagonal strings to verify that the garden is a square? Complete the explanation.
e23

Because both pairs of opposite sides of the quadrilateral garden are congruent, the garden is a parallelogram. The garden is a
(select)
, because all four sides are congruent. If it can be proven that it is also a
(select)
, then the garden is a square. So, if the diagonals
(select)
, then the garden is a square. The club members can measure the lengths of the diagonals.
Mathematics
1 answer:
Dafna1 [17]3 years ago
5 0

Answer:

first blank is "rhombus"

second blank is "rectangle"

third blank is "are congruent"

Step-by-step explanation:

You might be interested in
Hello again! This is another Calculus question to be explained.
podryga [215]

Answer:

See explanation.

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

Functions

  • Function Notation
  • Exponential Property [Rewrite]:                                                                   \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Property [Root Rewrite]:                                                           \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)

Derivative Property [Addition/Subtraction]:                                                         \displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                 \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

We are given the following and are trying to find the second derivative at <em>x</em> = 2:

\displaystyle f(2) = 2

\displaystyle \frac{dy}{dx} = 6\sqrt{x^2 + 3y^2}

We can differentiate the 1st derivative to obtain the 2nd derivative. Let's start by rewriting the 1st derivative:

\displaystyle \frac{dy}{dx} = 6(x^2 + 3y^2)^\big{\frac{1}{2}}

When we differentiate this, we must follow the Chain Rule:                             \displaystyle \frac{d^2y}{dx^2} = \frac{d}{dx} \Big[ 6(x^2 + 3y^2)^\big{\frac{1}{2}} \Big] \cdot \frac{d}{dx} \Big[ (x^2 + 3y^2) \Big]

Use the Basic Power Rule:

\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} (2x + 6yy')

We know that y' is the notation for the 1st derivative. Substitute in the 1st derivative equation:

\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 6y(6\sqrt{x^2 + 3y^2}) \big]

Simplifying it, we have:

\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 36y\sqrt{x^2 + 3y^2} \big]

We can rewrite the 2nd derivative using exponential rules:

\displaystyle \frac{d^2y}{dx^2} = \frac{3\big[ 2x + 36y\sqrt{x^2 + 3y^2} \big]}{\sqrt{x^2 + 3y^2}}

To evaluate the 2nd derivative at <em>x</em> = 2, simply substitute in <em>x</em> = 2 and the value f(2) = 2 into it:

\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = \frac{3\big[ 2(2) + 36(2)\sqrt{2^2 + 3(2)^2} \big]}{\sqrt{2^2 + 3(2)^2}}

When we evaluate this using order of operations, we should obtain our answer:

\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = 219

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

5 0
2 years ago
Don't really understand can some1 help
IrinaK [193]
I can what do you need help with
8 0
3 years ago
Reflect figure E across the x-axis and then reflect across the y-axis. What is the resulting figure?
Andreas93 [3]

Answer:

2nd option, rectangle B

Step-by-step explanation:

After reflexion, the figure will be at the left side of x=-5

3 0
3 years ago
5X+17=7 PLEASE HELP FAST
BARSIC [14]

Answer:

-2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Henry wants to know the height of an outdoor sculpture. He measures the shadow of the outdoor sculpture and finds that it is 12
coldgirl [10]
Height of sculpture/shadow of sculpture = height of tower/shadow of tower

x/12 = 12/16
16x = 12*12
16x = 144
x = 144/16
x = 9

The sculpture is 9 meters tall
3 0
3 years ago
Other questions:
  • Which is bigger?83 ft or 786 in?
    9·2 answers
  • I need help ASAP due rn!
    6·1 answer
  • Solve the equation. <br> 5/6 x-4 = -2
    10·1 answer
  • There are 8 pints in a gallon. how would you convert 13 pints into gallons
    7·1 answer
  • What operation should you use to solve -6
    14·1 answer
  • Can somewon help me i eally need help
    7·2 answers
  • How do you convert 3 yards 2 feet to inches
    9·2 answers
  • Can someone help me with number 1 PLZ
    9·1 answer
  • Please Help me To solve this Problem
    9·1 answer
  • Pls explain pls this will help alot
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!