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3 years ago

13

On a math test, Janice answers 85% of the questions correctly. If she answered 17 questions correctly, how many questions are on

the test?
Please help me

1 answer:

alex41 [277]3 years ago

5 0

Answer:

20

Step-by-step explanation:

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I WILL GIVE BRAINLIEST

Travka [436]

Answer:

D.

Step-by-step explanation:

Ape x.

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2 years ago

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2x-14=-3x+6<br /><br>help with this equation???<br />

Sphinxa [80]

2x-14=-3x+6
You need to combine like terms and get all the x's on one side and the numbers on the other
2x+3x-14=6
5x=6+14
5x=20
now divide to get x alone
x=4

Hope that helps

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4 years ago

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Please help, its easy im just slow i need it done in 10 mins please help

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Step-by-step explanation:

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3 years ago

For which value of a will the equation 3(x-2)=a+3x have an infinite number of solution. A) 2 B) -6 C)6 D) -2

andrew11 [14]

I think is C or B
Because
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4 0

3 years ago

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Use the bionomial theorem to write the binomial expansion

MaRussiya [10]

Answer:

$\left(\frac{x}{2} + 3 y\right)^{4}=\frac{x^{4}}{16} + \frac{3}{2} x^{3} y + \frac{27}{2} x^{2} y^{2} + 54 x y^{3} + 81 y^{4}$

Step-by-step explanation:

$\left(\frac{1}{2}x+3y \right)^4=\left(\frac{x}{2}+3y \right)^4\\$

Binomial Expansion Formula:

$(a+b)^n=\sum_{k=0}^n \binom{n}{k} a^{n-k} b^k$ , also $\binom{n}{k}=\frac{n!}{(n-k)!k!}$

We have to solve $\left(\frac{x}{2} + 3 y\right)^{4}=\sum_{k=0}^{4} \binom{4}{k} \left(3 y\right)^{4-k} \left(\frac{x}{2}\right)^k$

Now we should calculate for $k=0, k=1, k=2, k=3 \text{ and } k =4;$

First, for $k=0$

$\binom{4}{0} \left(3 y\right)^{4-0} \left(\frac{x}{2}\right)^{0}=\frac{4!}{(4-0)! 0!}\left(3 y\right)^{4} \left(\frac{x}{2}\right)^{0}=\frac{4!}{4!}(81y^4)\cdot 1 =81 y^{4}$

It is the same procedure for the other:

For $k=1$

$\binom{4}{1} \left(3 y\right)^{4-1} \left(\frac{x}{2}\right)^{1}=54 x y^{3}$

For $k=2$

$\binom{4}{2} \left(3 y\right)^{4-2} \left(\frac{x}{2}\right)^{2}=\frac{27}{2} x^{2} y^{2}$

For $k=3$

$\binom{4}{3} \left(3 y\right)^{4-3} \left(\frac{x}{2}\right)^{3}=\frac{3}{2} x^{3} y$

For $k=4$

$\binom{4}{4} \left(3 y\right)^{4-4} \left(\frac{x}{2}\right)^{4}=\frac{x^{4}}{16}$

You can perform the calculations, I will not type everything.

The answer is the sum of elements calculated.

Just organizing:

$\left(\frac{x}{2} + 3 y\right)^{4}=\frac{x^{4}}{16} + \frac{3}{2} x^{3} y + \frac{27}{2} x^{2} y^{2} + 54 x y^{3} + 81 y^{4}$

8 0

3 years ago

Read 2 more answers