There are 30 students in a year 6 class.

Find the distance between points.

SashulF [63]

Answer:

3 units

Step-by-step explanation:

Here, The distance between two points is 3 units

-TheUnknownScientist

4 0

2 years ago

Your family is installing a new square pool in the backyard. The existing patio has a side length of 8 feet. How much of the pat

trasher [3.6K]

The question is an illustration of perimeters.

The amount of patio to remove to install the pool is 8 feet.

From the question, we have:

$\mathbf{Length\ of\ the\ pool = 8}$

$\mathbf{Length\ of\ walkway = 1}$

The perimeter of the patio is:

$\mathbf{P_p = 4 \times Length\ of\ the\ pool}$

$\mathbf{P_p = 4 \times 8}$

$\mathbf{P_p = 32}$

A 1ft walkway means that;

1ft would be subtracted from both sides of the patio before installing the pool

So, the perimeter of the patio in terms of the length of the pool is:

$\mathbf{P_p = 4 \times (x +2)}$

Equate both expressions

$\mathbf{P_p = P_p}$

$\mathbf{4 \times (x +2) = 32}$

Divide both sides by 4

$\mathbf{x +2 = 8}$

Subtract 2 from both sides

$\mathbf{x = 6}$

So, the perimeter of the pool is:

$\mathbf{P_{pool} = 4 \times 6}$

$\mathbf{P_{pool} = 24}$

The amount of patio to remove is:

$\mathbf{Amount = P_p - P_{pool}}$

So, we have:

$\mathbf{Amount = 32 - 24}$

$\mathbf{Amount = 8}$

Hence, 8ft of the patio would be removed to install the pool

See attachment for illustration

Read more about perimeters at:

brainly.com/question/6465134

7 0

1 year ago

A bag contains 18 coins consisting of quarters and dimes. The total value of the coins is $2.85. Which system of equations can b

tatuchka [14]

There's nothing here to choose from but it should be something like : q + d = 18; .25q + .10d = 2.85

5 0

3 years ago

Read 2 more answers

Write the number 6 and 1 tenths in decimal form , words

ioda

6 and 1 tenths is 6.1 and six and one tenth.

8 0

2 years ago

Read 2 more answers

Need 2 more. 50 points! Please show work, Thanks! :)

rjkz [21]

Answer:

1) C

2) C

Step-by-step explanation:

Question 1)

We want a parabola that has the vertex (-8, -7) and also passes through the point (-7, -4).

So, we can use the vertex form. Remember that the vertex form is:

$y=a(x-h)^2+k$

Where a is our leading co-efficient and (h, k) is our vertex.

We know that our vertex is (-8, -7). So, substitute this into the equation:

$y=a(x-(-8))^2+(-7)$

Simplify:

$y=a(x+8)^2-7$

Now, we need to determine the value of our a. To do so, we can use the point the problem had given us. We know that the graph passes through (-7, -4).

So, when x is -7, y is -4. Substitute -7 for x and -4 for y:

$(-4)=a((-7)+8)^2-7$

Solve for a. Add within the parentheses:

$-4=a(1)^2-7$

Square:

$-4=a-7$

Add 7 to both sides. Therefore, the value of a is:

$a=3$

So, our entire equation in vertex form is:

$y=3(x+8)^2-7$

Our answer is C.

Question 2)

We are given a graph and are asked to find the equation of the graph.

Again, let's use the vertex form. From the graph, we can see that the vertex is at (-2, 2). Let's substitute this into our vertex equation:

$y=a(x-(-2))^2+2$

Simplify:

$y=a(x+2)^2+2$

Again, we need to find the value of a.

Notice that the graph crosses the point (-1, 5).

So, let's substitute -1 for x and 5 for y. This yields:

$5=a((-1)+2)^2+2$

Solve for a. Add within the parentheses.

$5=a(1)^2+2$

Square:

$5=a+2$

Subtract 2 from both sides. So, the value of a is:

$a=3$

Therefore, our entire equation is:

$y=3(x+2)^2-2$

Our answer is C.

And we're done!

3 0

3 years ago