There are 30 students in a year 6 class.
1 answer:
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Hey there, Brainiac!
To start this off, let's subtract LW from both sides of the equation.
S - LW = WH + HL
Now, let's use the distributive property on WH+HL.
Using the distributive property, we can change that to H(W+L)
S - LW = H(W+L)
Now, to finish this off, let's divide both sides by (W+L)
That's your answer.
Have an awesome day! :)
~collinjun0827, Junior Moderator
To start this off, let's subtract LW from both sides of the equation.
S - LW = WH + HL
Now, let's use the distributive property on WH+HL.
Using the distributive property, we can change that to H(W+L)
S - LW = H(W+L)
Now, to finish this off, let's divide both sides by (W+L)
That's your answer.
Have an awesome day! :)
~collinjun0827, Junior Moderator
Remember, an=a1(r)^(n-1) where a1=first term or where n=1 and r=commmon ratio
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a2/a1=r
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so if you have the graph, find the y value coresponding to x=1 and that is a1
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find the y value coresponding to x=2 and taht is a2, do a2/a1 to get r
so like I was saying
well, each term is 1/2 of the previous
20/40=1/2
so r=1/2
and a1=40
so
is da equation
so like I was saying
well, each term is 1/2 of the previous
20/40=1/2
so r=1/2
and a1=40
so