The result is my present age. What is my present age?
1 answer:
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Answer:
The administrator should sample 968 students.
Step-by-step explanation:
We have to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Z-table as such z has a p-value of .
That is z with a p-value of , so Z = 1.555.
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
Standard deviation of 300.
This means that
If the administrator would like to limit the margin of error of the 88% confidence interval to 15 points, how many students should the administrator sample?
This is n for which M = 15. So
Dividing both sides by 15
Rounding up:
The administrator should sample 968 students.