Let the number of bags of feed type I to be used be x and the number of bags of feed type II to be used be y, then:
We are to minimize:
C = 4x + 3y
subject to the following constraints:

From the graph of the 4 constraints above, the corner points are (0, 5), (1, 2), (4, 0).
Testing the objective function for the minimum corner point we have:
For (0, 5):
C = 4(0) + 3(5) = $15
For (1, 2):
C = 4(1) + 3(2) = 4 + 6 = $10
For (4, 0):
C = 4(4) + 3(0) = $16.
Therefore, the combination that yields the minimum cost is 1 bag of type I feed and 2 bags of type II feed.
Thw number 4,592 is roiundeth to 4500
Answer:
9.3
Step-by-step explanation:
35-7=28
28 divided by 3 = 9.3
Or $9 and 3 cents
Answer:
8/5
Step-by-step explanation:
Answer:
The solution and complete explanation for the above question and mentioned conditions is given below in the attached document. I hope my explanation will help you in understanding this particular question.
Step-by-step explanation: