First integral
Since
is a linear function, its graph is a line. This means that you can decompose the area under its graph as the sum of a right triangle and a rectangle, as shown in the attached image.
All the dimensions are fairly easy to deduce: we have

So, the area of the triangle is

For the rectangle, we have

So, the total area is 
Second integral
We have

So, this function is the upper half of the unit circle (the two halves are the functions
)
Since the area of the unit circle is
, the value of the integral is 
Third integral
It follows the exact same logic as the first one, you only have to adjust the numbers.
The amount of distance the wheel rolled is the circumference of that wheel. So we know the circumferenece of the wheel is 35cm; this is important because the formula for finding circumference is

. We can solve this for radius.

Divide by 2.

Divide by


So we now know the radius of the wheel is 5.57. We can then use this knowledge to find the area of the wheel. The formula for area is


Square 5.57.

Multiply by


This means the answer is the last one in the list given.
Y - 3 = 1/3(x - 6)
y - 3 = 1/3 x -2
y = 1/3 x - 2 + 3
y = 1/3 x - 1
Answer ⇒ y = 1/3 x - 1
Answer:
113.04
Step-by-step explanation:
Answer:
GDFGFDGFDGD
Step-by-step explanation:
YRUTUYTHDFGFD