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Alekssandra [29.7K]
2 years ago
15

A spinner with sections Red, Blue, Yellow, and Green is spun 3 times. What is the

Mathematics
1 answer:
Nostrana [21]2 years ago
3 0

Answer:

33.3%

Step-by-step explanation:

100 divided by 3 is 33.3

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01-1-
klio [65]

Answer:

Step-by-step explanation:

50 dollars = ∉34

∉1 = Rs 150

Rs 382800 / 150 Rs per ∉  =  382800/150 ∉

=2552 ∉

50 dollars = ∉34          so 50/34 dollars = ∉

2552 ∉ × 50/34 dollar per ∉ =       in the units the ∉ cancel out

                                                         ∉ × dollar/∉    = dollars

(2552 × 50) / 34    = 3752.94 dollars     <------------------

Here is another way of looking at the answer...........

Rs 382800 × 1∉/150 Rs × 50 dollars/34 ∉ =              note how the units cancel

= 382800 × (1/150) × (50/34)                          Rs × ∉/Rs × dollars/∉

=  3,752.94 dollars                                     leaving only dollars in the numerator

7 0
3 years ago
*PLEASE ANSWER!!! , I WILL MARK BRAINLIEST!! , ASAP!!*
tamaranim1 [39]

A country's income distribution is the <em>distribution of total GDP among the total population</em>

<em>hope it helps</em>

5 0
3 years ago
A point is plotted on the number line at 225 . A second point is plotted at −434 .
malfutka [58]

Answer:

7 3/20

Step-by-step explanation:

I took the quiz.

7 0
3 years ago
Can somebody help. 7 out of 10 is what percent?
Otrada [13]

Answer:

70%

Step-by-step explanation:

Multiply by ten and you get your percent

3 0
3 years ago
Read 2 more answers
A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.
irakobra [83]

Answer:

The integral is equal to 5\sec^2(2x)+C for an arbitrary constant C.

Step-by-step explanation:

a) If u=\tan(2x) then du=2\sec^2(2x)dx so the integral becomes \int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C. (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case u=\sec(2x) hence du=2\tan(2x)\sec(2x)dx. We rewrite the integral as \int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C.

c) We use the trigonometric identity \tan(2x)^2+1=\sec(2x)^2 is part b). The value of the integral is 5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C. which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.  

3 0
3 years ago
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